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Murljashka [212]
2 years ago
11

Can some help me i don't understand how to do this math!!

Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
6 0

Answer:

Step-by-step explanation:

\frac{x}{(x-2)^{2} } -\frac{x}{(x-2)(x-1)} = \frac{x^{2}-x-x^{2} +2x }{(x-2)^{2}(x-1) }

? = 2x -x = x

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Find the cube root of 27d3 + 54a2b + 36ab2 + 8b3​
enot [183]

Answer:

 (3a + 2b)3

Step-by-step explanation:

STEP 1  :

Equation at the end of step 1

 (((27•(a3))+((54•(a2))•b))+(36a•(b2)))+23b3

Step 2:

(((27•(a3))+((54•(a2))•b))+(22•32ab2))+23b3

Step 3:

(((27•(a3))+((2•33a2)•b))+(22•32ab2))+23b3

Step 4:

 ((33a3 +  (2•33a2b)) +  (22•32ab2)) +  23b3

Step 5:

 Factoring:  27a3+54a2b+36ab2+8b3

8 0
3 years ago
Sally's pet grooming business charges $5 per cat and $10 per dog for a pet bath. She earned $550 for pet baths last month. If 20
Minchanka [31]

Answer:

45 dogs

Step-by-step explanation:

so she has $550 and she did 20 cats and it costs $5 per cat and 5 x 20 is $100 and $550 - $100 = 450 and 450 divided by 10 ( because it's $10 per dog) is 45.

8 0
3 years ago
10. Write an equation in point-slope form and slope-intercept form for the line.
olga2289 [7]

We can use the points (2, -2) and (4, -1) to solve.

Slope formula: y2-y1/x2-x1

= -1-2/4-(-2)

= -3/6

= -1/2

Point slope form: y - y1 = m(x - x1)

y - 2 = -1/2(x + 2)

Solve for y-intercept.

-2 = -1/2(2)  + b

-2 = -1 + b

-2 + 1 = -1 + 1 + b

-1 = b

Slope Intercept Form: y = mx + b

y = -1/2x - 1

______

Best Regards,

Wolfyy :)

5 0
3 years ago
Which features describe the graph? Select all that apply
victus00 [196]

Answer:

- Decreasing  

Step-by-step explanation:

im not sure of the last two but the others are for sure a no

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E2%20%5Cleft%28%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B2%7D%20%20%2B%20
Verizon [17]

If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx

Let f(x) = \sqrt{1 + x^3}. Compute the inverse:

f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}

and we immediately notice that f^{-1}(x+1)=\sqrt[3]{x^2+2x}.

So, we can write the given integral as

\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx

Splitting up terms and replacing x \to x-1 in the first integral, we get

\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}

7 0
2 years ago
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