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Murljashka [212]
2 years ago
11

Can some help me i don't understand how to do this math!!

Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
6 0

Answer:

Step-by-step explanation:

\frac{x}{(x-2)^{2} } -\frac{x}{(x-2)(x-1)} = \frac{x^{2}-x-x^{2} +2x }{(x-2)^{2}(x-1) }

? = 2x -x = x

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A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

7 0
3 years ago
Students received grades with or - (example B ). Of all students who received one or more plus grades, 92% were undergraduates a
MrMuchimi

Answer:

The probability that a student is an undergraduate student, given that the student received a plus grade is 0.92

Step-by-step explanation:

The conditional probability of an event <em>B</em> given that another event <em>A</em> has already occurred is:

P(B|A)=\frac{P(A\cap B)}{P(A)}

Denote the events as follows:

<em>X</em> = a students is a graduate

<em>Y </em>= a students is a under-graduate

+ = a student received one or more plus grades

- = a student received one or more minus grades

Consider the tree diagram below.

According to the tree diagram, the probability that a student is an undergraduate student, given that the student received a plus grade is:

P (+ | Y) = 0.92

Thus, the probability that a student is an undergraduate student, given that the student received a plus grade is 0.92.

8 0
3 years ago
The expression
kobusy [5.1K]

Answer:

According yo my calculations v=-92 that makes it so that 34×6÷39=124

4 0
3 years ago
Read 2 more answers
X-cubed+3x-squared+5x+8/x+1
Blababa [14]
X^3+3x^2+5x+8/x+1
multiply the whole equation by x
x^4+3x^3+5x^2+8+1x
x^4+3x^3+5x^2+x+8
factor out by parts
(x^2-0.641604x+1.33244)(x^2+3.6416x+6.00403)
4 0
2 years ago
-3x to the fourth power -3x to the third power+x squared-2x to the third power -xsquared -8x +6
Ede4ka [16]

Given the sum:

\begin{gathered} -3x^4-3x^3+x^2 \\ \ldots\ldots-2x^3-x^2-8x+6 \end{gathered}

The sum is given below:

Therefore, the sum of the polynomials is:

-3x^4-5x^3-8x+6

5 0
11 months ago
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