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saveliy_v [14]
3 years ago
5

Find the equation of the line passes through (2,5) and perpendicular to 2x + 3y=5

Mathematics
1 answer:
finlep [7]3 years ago
4 0

Answer:

y - 5 = (3/2)(x - 2)

Step-by-step explanation:

If two lines are perpendicular, their slopes are negative reciprocals of one another.

The slope of 2x + 3y = 5 is found by solving this equation for y:

3y = -2x + 5, or y = (-2/3)x + 5/3.

Thus, the slope of the new line is the negative reciprocal of -2/3, which in turn comes out to 3/2.

Use the point-slope formula y - k = m(x - h):

Substituting the givens, we get  y - 5 = (3/2)(x - 2)

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Because 4 to the power of 2 is 16.

Then, you subtract: 16x - 7x

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Answer:

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