2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer: Infinite Solutions
Step-by-step explanation: Make the top x and y values times -2 to cancel all the variables and numbers out to get 0 = 0 so it would be Infinite Solutions.
And if you multiply by 2 you get the exact same equation.
If I am wrong let me know!
Hope this helps!
Answer:
1408 multiply 64 by 22 for a total of 1,408
Answer:
15. 1/3 times 1/3 times 1/3 times 1/3 and 1/81
16. 3/4 times 3/4 and 9/16
17. 2 to the 5th power
18. 4 to th2 4th power
19. 2 to the 4th power, 5 to the 2nd power, and 3 to the 3rd power
Step-by-step explanation:
Hope this helps
