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2 years ago

What’s the end behavior of g(x)=(5^x-3)+2.5

Mathematics

1 answer:

fomenos2 years ago

3 0

Hello from MrBillDoesMath!

Answer: g(x) approaches "infinity' as x approaches "positive infinity" and g(x) approaches --0.5 as x approaches "negative infinity"

Discussion.

g(x) = ( 5^x -3) + 2.5

Suppose x is approaching positive infinity. Then the term 5^x grows without bound ("positive infinity") so the -3 and "2.5" constants have no impact at all. That is, g(x) behaves like 5^x which grows without bound.

Suppose x is approaching negative infinity. Then 5^x approaches 0 (zero) so g(x) approaches

(0 -3) + 2.5 -

= - 0.5

Thank you,

MrB

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