Answer:
The maximum possible area is 1,600 m.
Step-by-step explanation:
You already have the two sides so you just multiply 40×40 and that gives you the area.
For this case we have the following equation:
Q = Av
Where the area is given by:
A = pi * r ^ 2
A = pi * (d / 2) ^ 2
A = (pi / 4) * d ^ 2
Substituting we have:
Q = ((pi / 4) * d ^ 2) v
From here, we clear the diameter:
d = root ((4 / pi) * (Q / v))
Substituting values we have:
d = root ((4 / pi) * (50/600))
d = 0.36 feet
Answer:
The diameter of a pipe that allows a maximum flow of 50ft ^ 3 / min of water flowing at a velocity of 600ft / min is:
d = 0.36 feet
First find the slope of the line = (y2 - y1) / (x2 - x1) where the 2 points are (x1, y1 and (x2, t2).
Then substitute the values of the slope (m) and one of the points into the point-slope formula
y - y1 = m(x - x1)
Answer:
So we have two given angles- 31* and 43*.
First we add those together.
31* + 43* = 74*
Then, we subtract that amount from 180*
180* - 74* = 106*
106* is the missing angle.
x106* - 31* = 75*
x106* + 43* = 149*
~Hope this helps~
