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3 years ago

15

Need help on what it is!!!

2 answers:

Harman [31]3 years ago

6 0

Km pretty sure it’s C (the third one )

Daniel [21]3 years ago

6 0

It's not C. Use the Geometric Mean for right triangles to solve. In our formula, our values will fit in like this: $\frac{9}{x}=\frac{x}{9+7}$ . Simplifying we have $\frac{9}{x}=\frac{x}{16}$ . Cross-multiply to get $x^2=144$ . That means that x = 12. First choice above.

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Some one answer and if u can explain.

grigory [225]

I D K WHAT THE ANSWER IS

8 0

3 years ago

Check that 2b+b and 3b have the same value when b is 1,2, and 3. Do 2b+b and 3b have the same value for all values of b? Explain

Inessa [10]

Answer:

Expression 2b+b and 3b have same values for all values of b.

Step-by-step explanation:

Given the two expression $2b+b$ and $3b$ and values of b as 1, 2 and 3.

Consider first expression that is, $2b+b$ .

Substituting the value of $b=1$ ,

$2\left(1\right)+\left(1\right)=2+1=3$ ....1

Substituting the value of $b=2$ ,

$2\left(2\right)+\left(2\right)=4+2=6$ ....2

Substituting the value of $b=3$ ,

$2\left(3\right)+\left(3\right)=6+3=9$ ....3

Consider second expression that is, $3b$ .

Substituting the value of $b=1$ ,

$3\left(1\right)=3$ ....4

Substituting the value of $b=2$ ,

$3\left(2\right)=6$ ....5

Substituting the value of $b=3$ ,

$3\left(3\right)=9$ ....6

For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.

Therefore both expression are same for all values of b.

3 0

3 years ago

7 to the negative 3rd porwer times 7 to the negative 2nd porwer times 2 the 0 power divided by 7 to negative 1st power times 7 t

Jobisdone [24]

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

$\frac{x^a}{x^b}=x^{a-b}$

$x^0=1$

$(x^a)(x^b)=x^{a+b}$

$x^{-a}=\frac{1}{x^a}$

$\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=$

$\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=$

$\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=$

$(\frac{7^{-5}}{7^{-5}})(\frac{2^0}{2^3})=$

$(7^{-5-(-5)})(2^{0-3})=$

$(7^0)(2^{-3})=$

$\frac{1}{2^3}=$

$\frac{1}{8}$

7 0

3 years ago

If felicity plays 805 games and started in 569 of them in what fraction of the games did he start

slega [8]

Answer:

0.706

Step-by-step explanation:

Felicity started in games = 569

Total number of games = 805

=> Fraction = 569/805

=> Fraction = 0.706

3 0

3 years ago

Which scatterplot does NOT suggest a linear relationship between and y

iren2701 [21]

C; this is because the line of beat fit isn’t linear but curved in that one graph.

5 0

3 years ago