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tamaranim1 [39]
3 years ago
5

A polynomial function has a root of -4 with multiplicity of 4, a root of -1 with multiplicity of 3, and a root of 5 with multipl

icity 6. If the function has a positive leading coefficient and is of odd degree, which could be the graph of the function ?
Mathematics
2 answers:
Dmitrij [34]3 years ago
7 0

Answer:

To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.


Step-by-step explanation:


A polynomials is an equation with many terms whose leading term is the highest exponent known as degree. The degree or exponent tells how many roots exist. These roots are the x-intercepts.


This polynomial has roots -4, -1, and 5. This means the graph must touch or cross through the x-axis at these x-values. What determines if it crosses the x-axis or the simple touch it and bounce back? The even or odd multiplicity - how many times the root occurs.


In this polynomial:


Root -4 has even multiplicity of 4 so it only touches and does not cross through.


Root -1 has odd multiplicity of 3 so crosses through.


Root 5 has even multiplicity of 6 so it only touches and does not cross through.


Lastly, what determines the facing of the graph (up or down) is the leading coefficient. If positive, the graph ends point up. If negative, the graph ends point down. All even degree graphs will have this shape.


To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.

Alexeev081 [22]3 years ago
3 0

Answer: b

Step-by-step explanation:

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ikadub [295]

Answer:

Cosx=a/h

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2 years ago
Solve for q. -5(3-q) +4=5q-11
soldier1979 [14.2K]

Perform the indicated multiplication first:  -15 + 5q + 4 = 5q - 11

Note that 5q appears on both sides of this equation.  Cancelling, we get :

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4 0
2 years ago
A club raised 175% of its goal for a charity. The club raises $875. What was the goal?
charle [14.2K]

Answer: The goal was $500

======================================================

Work Shown:

x% = x/100

175% = 175/100 = 1.75

Let g be the goal, which is the amount of money the club wanted to raise

175% of goal = 175% of g = 1.75g

The expression 1.75g represents how much money was actually raised, which was $875. Set the two expressions equal to each other. Solve for g

1.75g = 875

g = 875/1.75 ....... divide both sides by 1.75

g = 500

The club's goal was to raise $500

Note how 75% of $500 is 0.75*500 = 375

When they raised 175% of the goal, this means they went 75% overboard and added on 375 additional dollars (on top of the 500 they wanted). So they got to 500+375 = 875 which lines up with the instructions. This helps verify the answer.

Or we can see that 1.75*g = 1.75*500 = 875 which helps confirm the answer as well.

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3 years ago
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Answer:

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