13 multiplied by the sum of 4 and11. Now reverse the result and add it to the earliest result and then multiplied it by 13

Mathematics

1 answer:

Kobotan [32]2 years ago

4 0

Step-by-step explanation:

I am not critically certain but the ways you have jotted down your enquiry..

<h2>I assume is</h2>

13 × (4×11)

13 × 44

=572 - 44= 528

528+13 =541

541 ×13=7033

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The density of oxygen is 0.001429 grams per cubic centimeter. How is this number written in

Anika [276]

We have been given that the density of oxygen is 0.001429 grams per cubic centimeter. We are asked to write the given number in scientific notation.

To convert a number into scientific notation, we write the given number as product of two numbers. One factor is a number between 1 and 10, while the 2nd factor is power of 10.

When a decimal is to the left of given number, then we need to move the decimal to right such that the number gets between 1 and 10. Then, we multiply the number by negative power of 10 that many times, we moved the decimal to right.

We can see that decimal is to left of our number. To place decimal after 1, we have to multiply 10 to 3 times. To keep the value of number same we will multiply the same negative power (negative 3).

$0.001429\times 10^3\times 10^{-3}$

$(0.001429\times 10^3)\times 10^{-3}$

$(1.429)\times 10^{-3}$

$1.429\times 10^{-3}$

Therefore, the number 0.001429 will be $1.429\times 10^{-3}$ in scientific notation.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%7D-1%7D%7B2-5a%7D%20times%20%5Cfrac%7B15a-6%7D%7Ba%5E%7B2%7D%2B5a-6%7D" id=

stepan [7]

$\bf \cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\\\\
-----------------------------\\\\
recall\quad \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
thus\quad a^2-1\iff a^2-1^2\implies (a-1)(a+1)
\\\\\\
now\quad a^2+5a-6\implies (a+6)(a-1)\\\\
-----------------------------\\\\
thus
\\\\\\
\cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\implies \cfrac{(a-1)(a+1)}{2-5a}\times \cfrac{3(5a-2)}{(a+6)(a-1)}\\\\
-----------------------------\\\\
$

$\bf now\quad 3(5a-2) \iff -3(2-5a)\\\\
-----------------------------\\\\
thus
\\\\\\
\cfrac{\underline{(a-1)}(a+1)}{\underline{2-5a}}\times \cfrac{-3\underline{(2-5a)}}{(a+6)\underline{(a-1)}}\implies \cfrac{-3(a+1)}{a+6}$

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