All categories

3 years ago

In an arithmetic sequence , the 6th term is 9 and the 8th term is 15

1 answer:

8 0

Hopefully the math terms won't confuse anyone.

So in the series, a_6 = 9 and a_8 = 15. Since it's an arithmetic sequence, all the terms in the series can be represented as:
a_n = a_0 + n * k
where n is the nth number. K is a constant you add to reach the next term, and a_0 is the starting constant.
a_6 = a_0 + 6 * k
a_8 = a_0 + 8 * k
solving this system gives you that
k = 3 and a_0 = -9
for any term n for this arithmetic sequence,
a_n = -9 + 3 * k

You might be interested in

3 to the 2 power plus (9-5)

QveST [7]

Answer:

${3}^{2} + (9 - 5) \\ = 9 + 4 \\ = 13$

3 0

2 years ago

Read 2 more answers

PLEASE I REALLY NEED HELP!

vagabundo [1.1K]

Answer:

$\frac{3}{28}$

Step-by-step explanation:

Probability (P) is calculated as

P = $\frac{requiredoutcome}{count}$

The first required outcome is a red sweet from a total of 3 + 5 = 8

P( red) = $\frac{3}{8}$

There are now 2 red left and a count of 7, since 1 has been eaten, thus

P( second red ) = $\frac{2}{7}$

P( red and red ) = $\frac{3}{8}$ × $\frac{2}{7}$ = $\frac{6}{56}$ = $\frac{3}{28}$

6 0

3 years ago

Could someone help me find the velocity of the object pls im stuck

Mila [183]

Answer:

10 m/s

Step-by-step explanation:

Velocity= Position/Time

You can take any point on the line to calculate velocity.

Lets take t=1s

At t=1, position=10m

velocity= 10m/1s

=10 m/s

You can take any other point too, velocity will remain same.

For eg.

At t=5s

position=50m

velocity=50/5

=10m/s

Hope it helps :-)

5 0

3 years ago

Read 2 more answers

How do you divide 4÷236

iren [92.7K]

4 divided by 236 equals to 0.016

6 0

3 years ago

Express the function graphed on the axes below as a piecewise function.

adoni [48]

Answer:

f(x) = {x-3 for x ≤ -1; -3x+14 for x > 5}

Step-by-step explanation:

To write the piecewise function, we can consider the pieces one at a time. For each, we need to define the domain, and the functional relation.

<h3>Left Piece</h3>

The domain is the horizontal extent. It is shown as -∞ to -1, with -1 included.

The relation has a slope (rise/run) of +1, and would intersect the y-axis at -3 if it were extended.

The first piece can be written ...

f(x) = x-3 for x ≤ -1

<h3>Right Piece</h3>

The domain is shown as 5 to ∞, with 5<em> not included</em>.

The relation is shown as having a slope (rise/run) of (-3)/(1) = -3. If extended, it would intersect the point (5, -1), so we can write the point-slope equation as ...

y -(-1) = -3(x -5)

y = -3x +15 -1 = -3x +14

The second piece can be written ...

f(x) = -3x +14 for x > 5

<h3>Whole function</h3>

Putting these pieces together, we have ...

$\boxed{f(x)=\begin{cases}x-3&\text{for }x\le-1\\-3x+14&\text{for }5 < x\end{cases}}$

_____

<em>Additional comment</em>

Sometimes it is convenient to write inequalities in number-line order (using < or ≤ symbols). This gives a visual indication of where the variable stands in relation to the limit(s). Perhaps a more conventional way to write the domain for the second piece is, <em>x > 5</em>.

3 0

2 years ago