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Oksana_A [137]
3 years ago
14

A store sold 650 bicycles last year. this year the store sold 572 bicycles. what is the precent decrease in the number of bicycl

es sold from last year to this year ?
Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0
%change=100(572-650)/650= -12%

The sales decreased by 12%
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the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width
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  • Length = 17 inches

  • Width = 12 inches

⠀

Step-by-step explanation:

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As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

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Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

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Now, <u>According to the Question :</u>

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{\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}

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{\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}

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{\longrightarrow \qquad { {\sf{2 ( 2x + 5  )= 58 }}}}

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{\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}

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{\longrightarrow \qquad { {\sf{ 4x = 58  - 10}}}}

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{\longrightarrow \qquad { {\sf{ 4x = 48}}}}

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{\longrightarrow \qquad { {\sf{ x =  \dfrac{48}{4} }}}}

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{\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\:  \:  \bigstar

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Therefore,

  • The width of the rectangle is 12 inches .

⠀

Now, We are to find the length of the rectangle:

{\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}

⠀

Therefore,

  • The length of the rectangle is 17 inches .

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