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Oksana_A [137]
4 years ago
14

A store sold 650 bicycles last year. this year the store sold 572 bicycles. what is the precent decrease in the number of bicycl

es sold from last year to this year ?
Mathematics
1 answer:
allochka39001 [22]4 years ago
5 0
%change=100(572-650)/650= -12%

The sales decreased by 12%
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According to a​ survey, 65​% of murders committed last year were cleared by arrest or exceptional means. Fifty murders committed
monitta

Answer:

a) P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421

b) P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714

P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502

P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319

And adding these values we got:

P(36 \leq X \leq 38)= 0.1535

c) We can find the expected value given by:

E(X) = np =50*0.65 = 32.5

And the standard deviation would be:

\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

\mu -2\sigma = 32.5- 2*3.373 = 25.75

And then we can consider a value of 18 as unusual lower for this case.

Step-by-step explanation:

Let X the random variable of interest "number cleared by arrest or exceptional", on this case we can model this variable with this distribution:

X \sim Binom(n=50, p=0.65)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

We want this probability:

P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421

Part b

We want this probability:

P(36 \leq X \leq 38)

We can find the individual probabilities:

P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714

P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502

P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319

And adding these values we got:

P(36 \leq X \leq 38)= 0.1535

Part c

We can find the expected value given by:

E(X) = np =50*0.65 = 32.5

And the standard deviation would be:

\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

\mu -2\sigma = 32.5- 2*3.373 = 25.75

And then we can consider a value of 18 as unusual lower for this case.

6 0
4 years ago
Which expressions are equivalent to -f-5(2f-3)
gizmo_the_mogwai [7]

Answer:

-11f +15

Step-by-step explanation:

-f-5(2f-3)

Distribute

-f -10f +15

Combine like terms

-11f +15

3 0
3 years ago
Read 2 more answers
The normal yearly growth of a plant is 60 inches. The normal growth was ten inches more than twice the amount of last year. What
Usimov [2.4K]

The growth of the plant last year was 25 inches if the normal growth was ten inches more than twice the amount of last year.

<h3>What is linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The normal yearly growth of a plant is 60 inches.

Let's suppose the growth of the plant last year was x

The normal growth was ten inches more than twice the amount of last year.

From the above statement:

10 + 2x = 60

2x = 50

x = 25 inches

Thus, the growth of the plant last year was 25 inches if the normal growth was ten inches more than twice the amount of last year.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

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2 years ago
Converting a decimal to a mixed number as a improper fraction
Juli2301 [7.4K]
7 2/10 (or 7 1/5)
36/5
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3 years ago
A cup slides off a 2.5 m high table with a speed of 2.8 m/s to the right. We can ignore air resistance. What was the cup's horiz
azamat

Answer:

Horizontal distance = 1.98 m (Approx)

Step-by-step explanation:

Given:

Height = 2.5 m

Speed v = 2.8 m/s

Find:

Horizontal displacement

Computation:

s = ut + (1/2)gt²

2.5 = (1/2)(9.8)t²

t² = 0.5102

t = 0.7079 s

Horizontal distance = (v)(t)

Horizontal distance = (2.8)(0.7079)

Horizontal distance = 1.98 m (Approx)

5 0
3 years ago
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