Answer: Hello!
Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)
We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.
The total number of permutations is the product of the number of options that you have for each letter, this is:
17*16*15*14*....*3*2*1 = 17! = 3.6e+14
(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is
30! = 2.65e+32
(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.
then P = 47! = 2.59e+59
(d) DERMATOGLYPHICS: here are 18 letters, then:
p = 18! = 6.4e+15
The given equation is:
t = 7 + 5q
where:
t is the total number of points
q is the questions answered correctly
We are given that the total of correct answers is 6 and we want to find the total number of points. Therefore, all we have to do is substitute with the number of answers in the given equation to get the total points as follows:
t = 7 + 5q
t = 7 + 5(6)
t = 7 + 30
t = 37 points
Yes since the four sides are always parallel in a square <span />
There’s no picture. Do it again and add the picture. Then we can see the scale