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Goryan [66]
4 years ago
7

The prime factors of 146

Mathematics
2 answers:
Alex787 [66]4 years ago
6 0
It's only prime numbers are 1and146 so none
kompoz [17]4 years ago
5 0
2 *  73
The prime factors of 146 are 2 * 73.
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My question is what is x-4<6 i dont know inequalities
PolarNik [594]

Answer:

x=6+4

x<10

(-∞,10)

Step-by-step explanation:

Inequalities are the greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

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3 years ago
7th grade math pls help
notsponge [240]
22 x 13 is 286 and 11 x r is 11r leaving you with 286=11r and then you have to divide each side by 11 and you get r = 26
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Find the slope-intercept equation of the line that passes through (0,1) and has a slope of -2/3
xeze [42]

Answer:

y = -2/3x + 1

Step-by-step explanation:

We already know the slope, so all we need to do is find the y-intercept. To find that, we need to plug the coordinates into the equation so far, which is,

y = -2/3x + b

1 = -2/3(0) + b

1 = 0 +b

1 = b

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7 0
3 years ago
An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of moving violations
dimulka [17.4K]

Answer:

a. 0.80

b. $80

Step-by-step explanation:

a. The expected value, E(Y) is the sum of: [(each of the possible outcomes) × (the probability of the outcome occurring)]. In more concrete terms, the expectation is what you would expect the outcome of an experiment to be on average:

E(Y)=S_yP(Y=y)\\\\=0\times 0.5+1\times 0.25+2\times 0.20+3\times 0.05\\\\=0.80

Hence the expected value E(Y) is 0.80

b. From a above we have the expectation as  E(Y)=0.80.

-The expected amount is calculated by multiplying  expectation by the surcharge:

Ex \ Amount= E(Y)\times surcharge\\\\=0.80\times 100\\\\=80

Hence, the expected amount of surcharge is $80

4 0
3 years ago
A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.
pav-90 [236]

Answer:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.25 represent the population standard deviation

n represent the sample size  

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

3 0
3 years ago
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