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ASHA 777 [7]
3 years ago
7

Dave collects rocks. he makes 12 groups of 10 rocks and has none left over. How many rocks does Dave have?

Mathematics
2 answers:
xxMikexx [17]3 years ago
8 0
12 groups, and each one containing 10. 
Think about it. Which operation could we use?

Multiplication!

12*10 = 120

Dave has 120 rocks. 

(One nice rock collection, Dave) 
;-) 
Firdavs [7]3 years ago
4 0
That means he has 120 rocks
12*10=120

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The length of the garden is 10 feet more than twice its width. The perimeter of the garden is 170 feet.
icang [17]

Answer:

The width of the garden is 25 feet

The length of the garden is 60 feet

Step-by-step explanation:

The formula for the perimeter of a rectangle

= P = 2L + 2W

Where L = Length, W = Width

The length of the garden is 10 feet more than twice its width.

P = 170

L = 2W + 10

Hence,

170 = 2(2W + 10) + 2W

170 = 4W + 20 + 2W

Collect like terms

170 - 20 = 6W

150 = 6W

W = 150/6

W = 25 feet

The width of the garden is 25 feet

Remember

L = 2W + 10

L = 2(25) + 10

L = 50 + 10

L = 60 feet

The length of the garden is 60 feet

3 0
2 years ago
You and your friend go to the movies and spend 40 dollars, if you want to split the bill evenly how much do you have to pay?
muminat

Answer:

you'll have to pay $20

Step-by-step explanation:

5 0
3 years ago
Solve for x.<br><br> 4 | x - 7 | + 2 | x - 7 | = 12
miv72 [106K]

Answer: x = 9, 5

<u>Step-by-step explanation:</u>

4 | x - 7 | + 2 | x - 7 | = 12

6 | x - 7 | = 12      <em>added like terms</em>

  | x - 7 | = 2       <em>divided both sides by 6</em>

x - 7 = 2         or         x - 7 = -2     <em>removed absolute value sign</em>

    x = 9         or               x = 5     <em>added 7 to both sides of both equations</em>

7 0
3 years ago
P(x) =x and q(x) = x-1Given:minimum x and Maximum x: -9.4 and 9.4minimum y and maximum y: -6.2 and 6.2Using the rational functio
Arte-miy333 [17]

we have the following function

\frac{p(x)}{g(x)}=\frac{x}{x\text{ -1}}

where x is between -9.4 and 9.4 and y is between -6.2 and 6.2.

We will first draw the function

from the graph, we can see that the zeroes are all values of x for which the graph crosses the x -axis

In this case, we see that that the only zero is at x=0.

Now, we have that the asymptotes are lines to which the graph of the function get really close to. On one side, we can see that as x goes to infinity or minus infinity, the values of the function get really close to 1. So the graph has a horizontal asymptote at y=1. Also, we can see that as x gets really close to 1, the graph gets really close to the vertical line x=1. So the graph has a vertical asymptote at x=1.

Recall that the domain of a function is the set of values of x for which the function is defined. From our graph, we can see that graph is not defined when x=1. So the domain of the function is the set of real numbers except x=1. Now, recall that the range of the function is the set of y values of the graph. From the picture we can see that the graph has a y coordinate for every value of y except for y=1. So, this means that the range of the function is the set of real numbers except y=1.

From the graph, we can see that we cannot draw the graph having a continous drawing. That is, imagine we take a pencil and start on one point on the graph on the left side. We can draw the whole graph on the left side, but we cannot draw the graph on the right side without lifting the pencil up. As we have to "lift the pencil up" this means that the graph is not continous

Finally note that as we have a vertical asymptote at x=1 and horizontal asymptote at y=1 we have that when y is 1 or x is 1, the function y=f(x)/g(x) is undefined

5 0
1 year ago
What mistake did she make while solving the problem?
umka2103 [35]

Answer:

Ms, Erickson added 6x^3 plus -3x^2 and these terms have different exponents.l

Step-by-step explanation:

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