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Step-by-step explanation:
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Answer:
2x-3/y-5/37=0
Step-by-step explanation:
here, given equation of line is
y=3/2x+3
or,y(2x+3)=3
or,2x+3=3/y
or,2x-3/y+3=0...eqn(i)
equation of any line parallel to line (i) is
2x-3/y+k=0.. eqn(ii)
since, the line passes through (4,5)[replacing x=4 and y=5 in eqn(ii), we get]
2*4-3/5+k=0
or,8-3/5+k=0
or,40-3/5+k=0
or,k=-5/37
substituting the value of k=-5/37 in eqn(ii)
2x-3/y-5/37=0 is the required equation of line.
Answer:
y = 3x + 6
Step-by-step explanation:
y = ax + b, and since we know the gradient =>
y = 3x + b
y(-1) = -3 + b = 3 => b = 6
Answer:
<em>Subtract 7 from c.</em>
<em>c - 7.</em>
