Step-by-step explanation:
so 5/9(86-32) then you take
86-32=(54)
now it look like C=5/9=(54)
C=30
so c=30 is the answer :)
The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
Read more about radius
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Answer:
B. (-r, 0)
Step-by-step explanation:
W is on the x axis, so the y coordinate is 0.
It is also r away from the origin, so the x coordinate is -r
Hope this helps!
Ans
I = sqrt(P/R)
Step-by-step explanation:
You divide both sides by R first
P/R = I^2 R/R
So,
I^2 = P/R
take the square root of both sides
I = sqrt(P/R)
