Answer:
26.75 units ^2
Step-by-step explanation:
Since the shape is complex, divide it into 3 right angled triangles and one square. Find the area of these individual shapes first, then fin the sum of these area to calculate the ultimate area of e complex shape:
Triangle 1 = 1/2 x 2 x 5 = 5 units ^2
Triangle 2 = 1/2 x 2 x 2 = 2 units ^2
Triangle 3 = 1/2 x 3.5 x 9 = 15.75 units ^2
Square = 2 x 2 = 4 units squared.
Now add all these up 15.75 + 2 + 5 + 4 = 26.75 units squared.
Hope this helps
Answer:
The answer is 36 units2
Step-by-step explanation:
I took the test so I’m right
Answer:
We know that lines <em>l</em><em> </em>and <em>m</em><em> </em>are parallel. The alternate interior angles rule states that the alternate interior angles formed by parallel lines are equal. So let's equate them.
2x + 22 = 4x
putting variables on one side,
22 = 4x - 2x
Thus 2x = 22
x becomes 22÷2
Therefore,<u> x = 11.</u>
pls give brainliest for the answer
Answer:
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
Step-by-step explanation:
IQR = Q₃ - Q₁
For the town A:
Q₃ = 40 and Q₁ = 20
IQR of town A = 40 - 20 = 20
For the town B:
Q₃ = 30 and Q₁ = 20
IQR of town A = 30 - 20 = 10
Check the given options:
The most statement is appropriate comparison of the spreads is B
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
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Not sure question is complete, assumptions however
Answer and explanation:
Given the above, the function of the population of the ants can be modelled thus:
P(x)= 1600x
Where x is the number of weeks and assuming exponential growth 1600 is constant for each week
Assuming average number of ants in week 1,2,3 and 4 are given by 1545,1520,1620 and 1630 respectively, then we would round these numbers to the nearest tenth to get 1500, 1500, 1600 and 1600 respectively. In this case the function above wouldn't apply, as growth values vary for each week and would have to be added without using the function.
On one hand, the function above could be used as an estimate given that 1600 is the average growth of the ants per week hence a reasonable estimate of total ants in x weeks can be made using the function.
