Answer:
CI =[- 4.588; 15.4]
Since the calculated value of t= 4.244 falls in the critical region so we reject H0 and conclude that we are not confident that the mean difference in lifetime between front and rear brake pads is 99.5%
Step-by-step explanation:
The given data is
Car Rear Front d= rear- front
1 40.6 32.5 8.1
2 35.4 27.1 8.3
3 46.6 35.6 11
4 47.3 35.6 11.7
5 38.7 30.3 8.4
6 51.2 41.1 10.1
7 50.6 40.7 9.9
8 45.9 34.3 11.6
<u>9 47.2 36.5 10.7</u>
∑ = 89.8
Let the hypotheses be
H0: ud= 0 against the claim Ha: ud ≠0
The degrees of freedom = n-1= 9-1= 8
The significance level is 0.05
The test statistic is
t= d`/sd/√n
The critical region is ║t║≤ t (0.025,8) = ±2.306
Sd= 7.05434553
d`=∑d/n= 89.8/9= 9.978
Therefore
t= d`/ sd/√n
t= 9.978/ 7.054/√9
t= 4.244
1) Since the calculated value of t= 4.244 falls in the critical region so we reject H0 and conclude that we are not confident that the mean difference in lifetime between front and rear brake pads is 99.5%
2) the confidence interval for the difference of two samples can be calculated by
d ` ± td sd/√n
9.978 ±2.306* 7.054/√9
- 4.588; 15.4
Domain is all real numbers
Range is [-3,∞)
So you will need 33/6 cups of flour for 3 batches
It would be letter D - 3648.
The probability of winning is 0.76 and the probability of losing is 0.24.
In each simulation the probability of winning exactly one match is: P(win one match) = 2C1 x 0.76 x 0.24 = 0.3648
Multiply the result by 10,000 simulations to get the expected number of times that exactly one match is won.
10,000 x 0.3648 = 3648 times.
<em>Answer:</em>
Complete proof is written below.
Facts and explanation about the segments shown in question :
- As BC = EF is a given statement in the question
- AB + BC = AC because the definition of betweenness gives us a clear idea that if a point B is between points A and C, then the length of AB and the length of BC is equal to the length of AC. Also according to Segment addition postulate, AB + BC = AC. For example, if AB = 5 and BC= 7 then AC = AB + BC → AC = 12
- AC > BC because the Parts Theorem (Segments) mentions that if B is a point on AC between A and C, then AC > BC and AC>AB. So, if we observe the question figure, we can realize that point B lies on the segment AC between points A and C.
- AC > EF because BC is equal to EF and if AC>BC, then it must be true that the length of AC must greater than the length segment EF.
Below is the complete proof of the observation given in the question:
<em />
<em>STATEMENT REASON </em>
___________________________________________________
1. BC = EF 1. Given
2. AB + BC = AC 2. Betweenness
3. AC > BC 3. Def. of segment inequality
4. AC > EF 4. Def. of congruent segments
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<em>Keywords: statement, length, reason, proof</em>
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