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Fittoniya [83]
3 years ago
13

The chance that two people both have three repeat sequences at location A is 1 in 500. The chance that two people have four repe

at sequences at location B is 1 in 800. What is the probability that two people have the same number of repeats in both location A and location B
Mathematics
1 answer:
olga55 [171]3 years ago
4 0

Answer: Probability that two people have the same number of repeats in both location A and location B is \dfrac{1}{40000Step-by-step explanation:Since we have given that Probability that two people both have 3 repeat sequences at location A = [tex]\dfrac{1}{500}

Probability that two people both have 4 repeat sequences at location B = \dfrac{1}{800}

P(A) =\dfrac{1}{500} and P(B) = \dfrac{1}{800}

Since A and B are independent events.

According to question,

P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\dfrac{1}{500}\times \dfrac{1}{800}\\\\P(A\cap B)=\dfrac{1}{40000}

Hence,  probability that two people have the same number of repeats in both location A and location B is \dfrac{1}{40000}

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