Question

The chance that two people both have three repeat sequences at location A is 1 in 500. The chance that two people have four repeat sequences at location B is 1 in 800. What is the probability that two people have the same number of repeats in both location A and location B

Answer 1

Answer: Probability that two people have the same number of repeats in both location A and location B is $\dfrac{1}{40000Step-by-step explanation:Since we have given that Probability that two people both have 3 repeat sequences at location A = [tex]\dfrac{1}{500}$

Probability that two people both have 4 repeat sequences at location B = $\dfrac{1}{800}$

P(A) =$\dfrac{1}{500}$ and P(B) = $\dfrac{1}{800}$

Since A and B are independent events.

According to question,

$P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\dfrac{1}{500}\times \dfrac{1}{800}\\\\P(A\cap B)=\dfrac{1}{40000}$

Hence,  probability that two people have the same number of repeats in both location A and location B is $\dfrac{1}{40000}$