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Alex Ar [27]
3 years ago
10

The major result of treating 1-butyne with 6M aqueous NaOH would be:_______.A. the production of an alkene.B. the production of

an alkane. C. the production of an enol. D. nothing, as the alkyne would not react to an appreciable extent. E. the production of the sodium alkynide.
Computers and Technology
1 answer:
andriy [413]3 years ago
6 0

Answer:

D. nothing, as the alkyne would not react to an appreciable extent.

Explanation:

Nothing, as the alkyne would not react to an appreciable extent.

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Suppose that the five measured SampleRTT values are 106 ms, 120 ms, 140 ms, 90 ms, and 115 ms.
jeyben [28]

Answer:

a) 100.75,   103.15,    107.756,    105.536,   106.72

b) 5.06,    8,       14.061,       14.43,    12.89

Explanation:

Measured sample RTT values : 106 ms, 120 ms, 140 ms,  90 ms,  115 ms

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∝ = 0.125

β = 0.25

First DevRTT value = 5 ms

<u>A)   Compute the EstimatedRTT after each of these SampleRTT values is obtained,</u>

Formula for estimated RTT = ( 1 - ∝ ) . estimated RTT + ∝.sample RTT

B). <u>Compute  the DevRTT after each sample is obtained,</u>

Formula for DevRTT = ( 1 - β ) . DevRTT + β. | sample RTT - Estimated RTT |

attached below is a detailed solution

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