Answer:
no
Step-by-step explanation:
no because some numbers could be negative and most number lines also contain 0. whole numbers are positive, non decimal/fractional, real numbers
Answer:
The total price of the groceries, including discount and tip is $110.4.
Step-by-step explanation:
Here, the bill amount of groceries = $120
Now, the coupon off = 20%
Calculating the discount, we get
20% of bill amount $120 = 20% of 120 = 
So, the 20% discount on the bill amount = $24
The actual payable amount = Bill Amount - Discount
= $120 - $24 = $96
Now, 15% tip is also applied on the actual payable amount $96.
15% of 96 = 
So, the total price t = Payable amount + Tip amount
= $96 + $14.4 = $110.4
or, t = $110.4
Hence, the total price of the groceries, including the discount and the tip is t = $110.4.
The actual value is 250.84 .
Formula
Percentage calculation =(given value/total value)*100
let the actual value is "x"
percentage we known is 59 1/5% (59.2%) and 59.2% of x is 148.5.
for the percentage,
x*59.2% =148.5
x*59.2/100=148.5
x=(148.5/59.2)*100
x=(2.5084)*100
x=250.84
The actual value is 250.84 .
Learn more about the percentage here:
brainly.com/question/14091961
#SPJ1
Answer:
D) 0.42 + 0.17 x = 0.93
Step-by-step explanation:
0.93 - 0.42 = 0.51
0.51 / 0.17 = 3
3 ounces and the answer is D
Complete question:
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.
A) Find the mean and standard deviation for the number of girls in groups of 36 births.
B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.
C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?
Answer:
a) mean = 18
Standard deviation =3
b) low range = 12
High range = 24
c) The result of 33 girls is significantly high. Yes, the method is effective.
Step-by-step explanation:
Given:
p = 0.5
n = 36
a) The mean is the product of n and p
Mean u = np
u = 36 * 0.5 = 18
The standard deviation is the square root of the product of n and p&q.
S.d ó = 


b) To find the range rule of thumb:
• For low range
Low range = u - 2ó
= 18 - (2 * 3)
= 12
• High range
= u + 2ó
= 18 + (2*3)
= 24
c) The result is significantly high, because 33 is greater than 24 girls.
A result of 33 girls would prove the method as effective.