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Stolb23 [73]
3 years ago
13

What is the radius of a circle whose equation is (x 5)2 (y-3)3 42?O 2 unitso 4 unitsO 8 units16 unitsSave and ExitMark this and

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Mathematics
2 answers:
dexar [7]3 years ago
4 0

we know that

the equation of the circle is of the form

(x-h)^{2} +(y-k)^{2} =r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

in this problem we have

(x+5)^{2} +(y-3)^{2} =4^{2}

so

the center is the point (-5,3)

the radius is 4\ units

therefore

the answer is

The radius of the circle is equal to 4\ units

katrin2010 [14]3 years ago
3 0
So what you marked there this 4 units this is true so you are right sure 

hope this will help you 
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Find the sum of (-4 + 1) and (10-51).
kogti [31]

Answer:

-44

Step-by-step explanation:

(-4+1)+(10-51)

-4+1+10-51

-3-41

-44

5 0
3 years ago
1 divided by 1/10... ya thats about it...​
Rina8888 [55]

Answer:

10

Step-by-step explanation:

8 0
2 years ago
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Answer:

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3 0
2 years ago
Giving out brainliest answer pls help
Whitepunk [10]

Take a two-digit number. The possible numbers for original number condition are 29, 38, 47, 56, 65, 74, 83, 92.

<u>SOLUTON: </u>

Given, Take a two-digit number. Write it backwards. Add it to the original number. If what you get is a perfect square,

We have to find what could be the original number? Find all answers

Now, let the original number be xy

Then, xy + yx is a perfect square.

⇒ (10x + y) + (10y + x) is perfect square

[ because we can write 21 as 2 x 10 + 1 ]

⇒ (11x + 11y) is a perfect square

⇒ 11(x + y) is perfect square.

11(x + y) to be perfect square x + y should also be 11.

Then, x + y = 11.

Now, possible values of x and y are (2, 9), (3, 8), (4, 7), (5, 6), (6, 5), (7, 4), (8, 3), (9, 1)

(10, 1) is not possible because x range is from 0 – 9 as we took it as digit in xy

Now, the originals numbers xy are 29, 38, 47, 56, 65, 74, 83, 92.

Hence, the possible numbers for original number condition are 29, 38, 47, 56, 65, 74, 83, 92.

7 0
3 years ago
GH= 7y+3, HI= 3y-5, and GI= 9y+7. A) What is the value of y? B) Find GH, HI, and GI.
Strike441 [17]
A )
9 y + 7 = 7 y + 3 + 3 y - 5
9 y - 7 y - 3 y = 3 - 5 - 7
- y = - 9
y = 9
B )
GH = 63 + 3 = 66
HI = 27 - 5 = 22
GI = 66 + 22 = 88 
4 0
3 years ago
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