The answer to your question is 92
You add 1/4 each year:
800 to 1000 in one year
1000 to 1250 in 2
1250 to around 1812.5
Answer:
The answer is A) 379.9
Step-by-step explanation:
3.14(11^2)
3.14*11^2
3.14*(11*11)
379.94 if rounded to the nearest tenth it would be 379.9
Sin30= opposite/hypotenuse
sin30= AC/10
AC= 4.5cm
Tan25= opposite/adjacent
Tan25= 4.5/ CD
CD= 10.7
Answer:
years worked: 14
at least 10 years: 73%
Step-by-step explanation:
The mean is found by adding the years of service and dividing by the number of employees. The total years of service is 417, so the average is ...
average years worked = 417/30 = 13.9 ≈ 14 . . . years
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The percentage of employees that have worked there at least 10 years is found by counting the number with 10 or more years of service and dividing that count by the total number of employees. The result is then expressed as a percentage.
(10 years or over)/(total number) = 22/30 = 0.73_3 (a repeating decimal) ≈ 73%
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Comment on the working
A spreadsheet can be helpful for this. It has a function that can calculate the mean for you. Sorting the years of service into order can make it trivially easy to count the number that are 10 or more, or you can write a function that will do the count for you. (Also, less than 10 means the years are a single digit. There are 8 single-digit numbers in your list.) The hard part is copying 30 numbers without error.
