So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Answer:
81a^2+16b^2
Step-by-step explanation:
Answer:
m = 1, b = -5 y = x -5
Step-by-step explanation:
first find the slope or m
slope is change in y over change in x
-8 - (-6) = -2
-3 - (-1) = -2
-2/-2 = 1
m = 1
y = x + b
use one of the points and solve for b
The answer to this question would be n^2+191n+18/4n
1. The two triangles are similar because the two pairs of angles are equal, therefore the third angles of both triangles must also be equal.
We can call this the AAA similarity criterion
2. To find QR, we must use ratios between 2 known similar sides of both triangles,

So, QR =1.02