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Ad libitum [116K]
3 years ago
5

What does c equal in this equation 6c + 11 = 2c + 59

Mathematics
1 answer:
irinina [24]3 years ago
8 0
Combine like terms you would get 4c=48 then divide it by 4 you'll get c=12
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In a polynomial do you identify how many terms are in a problem before or after you solve it?
dimaraw [331]

Answer:

All you have to do to identify the number of terms in a polynomial is to count the number of separate parts in the polynomial separated by a plus or minus (terms)

Step-by-step explanation:

7 0
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A set of numbers is shown below:
Snezhnost [94]
2 because 2(2) + 3 = 7
6 0
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Estimate how many 12-inch rulers will be about the same length as a sheet of paper.
Pani-rosa [81]
One or maybe a little less
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Add [1/-4 3/5] [-2/6 -2/4]
brilliants [131]

Answer:

​25/138

Step-by-step explanation:

1 Convert 4\frac{3}{5}4

​5

​

​3

​​  to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

​c

​

​b

​​ =

​c

​

​ac+b

​​ .

\frac{1}{-(\frac{4\times 5+3}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​4×5+3

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

2 Simplify  4\times 54×5  to  2020.

\frac{1}{-(\frac{20+3}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​20+3

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

3 Simplify  20+320+3  to  2323.

\frac{1}{-(\frac{23}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

4 Simplify  \frac{2}{6}

​6

​

​2

​​   to  \frac{1}{3}

​3

​

​1

​​ .

\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{2}{4})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​3

​

​1

​​ −

​4

​

​2

​​ )

5 Simplify  \frac{2}{4}

​4

​

​2

​​   to  \frac{1}{2}

​2

​

​1

​​ .

\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{1}{2})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​3

​

​1

​​ −

​2

​

​1

​​ )

6 Find the Least Common Denominator (LCD) of \frac{1}{3},\frac{1}{2}

​3

​

​1

​​ ,

​2

​

​1

​​ . In other words, find the Least Common Multiple (LCM) of 3,23,2.

LCD = 66

7 Make the denominators the same as the LCD.

-\frac{1\times 2}{3\times 2}-\frac{1\times 3}{2\times 3}−

​3×2

​

​1×2

​​ −

​2×3

​

​1×3

​​

8 Simplify. Denominators are now the same.

-\frac{2}{6}-\frac{3}{6}−

​6

​

​2

​​ −

​6

​

​3

​​

9 Join the denominators.

\frac{-2-3}{6}

​6

​

​−2−3

​​

10 Simplify  -\frac{1}{3}-\frac{1}{2}−

​3

​

​1

​​ −

​2

​

​1

​​   to  -\frac{5}{6}−

​6

​

​5

​​ .

\frac{1}{-(\frac{23}{5})}\times \frac{-5}{6}

​−(

​5

​

​23

​​ )

​

​1

​​ ×

​6

​

​−5

​​

11 Move the negative sign to the left.

-\frac{1}{\frac{23}{5}}\times \frac{-5}{6}−

​

​5

​

​23

​​

​

​1

​​ ×

​6

​

​−5

​​

12 Invert and multiply.

-\frac{5}{23}\times \frac{-5}{6}−

​23

​

​5

​​ ×

​6

​

​−5

​​

13 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

​b

​

​a

​​ ×

​d

​

​c

​​ =

​bd

​

​ac

​​ .

-\frac{5\times -5}{23\times 6}−

​23×6

​

​5×−5

​​

14 Simplify  5\times -55×−5  to  -25−25.

-\frac{-25}{23\times 6}−

​23×6

​

​−25

​​

15 Simplify  23\times 623×6  to  138138.

-\frac{-25}{138}−

​138

​

​−25

​​

16 Move the negative sign to the left.

-(-\frac{25}{138})−(−

​138

​

​25

​​ )

17 Remove parentheses.

\frac{25}{138}

​138

​

​25

​​

7 0
3 years ago
Using the product property of square roots what is the square root of 28 and 150
Svetllana [295]
I assume you need find out √28=√7*4=2√7
√150=√5*5*6=5√6
hope it helps
3 0
3 years ago
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