After 1st year: 250$:100%=x$:116%, 250$*116%=x$*100%, x=(250*116)/100=290$. After 1st year I will have 290$
After 2nd year: 290$:100%=x$:116%, x=(290*116)/100=336.4$. After 2nd year I will have 336.4$
After 3rd year I will have (336.4*116)/100=390.224$
After 4th yr: (390.224*116)/100=452.65984$
After 5th yr: (452.65984*116)/100=525.085$
After- 6th yr: 609.1$, 7th yr: 706.556$, 8th yr: 819.605$, 9th yr: 950.742$
10th yr: 1102.86$, 11th yr: 1279.32$, 12th yr: 1484.01$, 13th yr: 1721.45$,
14th yr: 1996.88$, 15th: 2316.38$, 16th yr: 2687$, 17th yr: 3116.92$
After 18 years I will have 3615.63$.
b = - 4
slope m = (0 + 4)/(4 - 0) = 4/4 = 1
equation
y = x - 4
We need to correctly choose exactly 4 out of the 6 drawn numbers.
Apply hypergeometric distribution:
a=number of correctly chosen numbers = 4
A=number of correct (drawn) numbers = 6
b=number of incorrectly chosen numbers = 2
B=number of undrawn numbers = 44-6 = 38
Then by the hypergeometric distribution
P(a,b,A,B)
=C(A,a)C(B,b)/C(A+B,a+b) [C(n,r)=combination of r objects taken out of n]
=C(6,4)C(38,2)/C(44,6)
=15*703/7059052
= 10545/7059052
= 0.001494 (to the nearest millionth)
Answer: probability of winning third prize is 10545/7059052=0.001494
Answer:
Step-by-step explanation:
-2y³ + 4 - (-3 - 2y³ - y - 5y²) = -2y³ + 4 + 3 + 2y³ + y + 5y²
= <u>-2y³ + 2y³ </u> +5y² + y +<u> 4 + 3</u> {combine like terms}
= 5y² +y + 7