The points on the graph of the inverse variation are of the form:
(x, 8/x)
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Which ordered pairs are on the graph of the function?</h3>
An inverse variation function is written as:
y = k/x.
Here we know that k = 8.
y = 8/x
Then the points (x, y) on the graph of the function are of the form:
(x, 8/x).
So evaluating in different values of x, we can get different points on the graph:
- if x = 1, the point is (1, 8)
- if x = 2, the point is (2, 4)
- if x = 3, the point is (3, 8/3)
- if x = 4, the point is (4, 2)
And so on.
If you want to learn more about inverse variations:
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I need a picture or something to answer this question
Hi there!
13y² + 10y - 3 = 5y²
Begin by moving all terms to one side:
13y² + 10y - 3 - 5y² = 0
Combine like terms:
8y² + 10y - 3 = 0
Factor using the guess-and-check method.
(4y - 1)(2y + 3) = 0
Set each factor equal to 0 to find the solutions:
4y - 1 = 0
4y = 1
y = 1/4
2y + 3 = 0
2y = -3
y = -3/2
Circumference of entire circle = 2 * PI * radius
2 * PI * 3 =
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18.8</span></span></span>5 meters
a 30 degree arc is (30/360) or 1/12 of a circle.
So the arc equals (18.85 meters / 12) or
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1.57</span></span></span> meters.
Answer:
Yellow is the answer
Step-by-step explanation:
