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3 years ago

5

You give up a full-time salary of $45,000 a year to go to school for 2 years. The total cost of going to school is $30,000. If y

ou want to be able to recover your investments in 5 years or less, what is the minimum salary you would need to earn upon earning your degree

1 answer:

My name is Ann [436]3 years ago

7 0

Just take your 30,000 devided by your 5 years for a answer of 6000 a year

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How to you write 1/25 using exponents

Montano1993 [528]

Answer:

$5^{-2}$

Step-by-step explanation:

Using the rule of exponents

$a^{-m}$ ⇔ $\frac{1}{a^{m} }$ , then

$\frac{1}{25}$ = $\frac{1}{5^{2} }$ = $5^{-2}$

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Avery has $3. She earns $1.20 for each chore she does. (She can complete fractions of

Sonja [21]

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She would have to do a chore 11.25 times

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3 years ago

Help me with #5 pleaseeeeeeeeeee

earnstyle [38]

Answer:

$\angle 1 = 45$ degrees

Step-by-step explanation:

Sum of 3 angles in a triangle is 180..

The angles given are:

60

7x + 12

1

So we sum to 180 and write:

$60+7x+12+\angle 1=180\\72+7x+\angle 1=180\\7x+\angle 1=108$

Also, straight angle is 180 degrees, thus Angle 1 and (14x + 9) angle is sum to 180, thus we can write:

$14x+9+\angle 1=180\\14x + \angle 1=171$

Or we can write this as:

$14x + \angle 1=171\\\angle 1 = 171 - 14x$

We substitute this expression for Angle 1 into 1st equation we got and solve for x first,

$7x+\angle 1 = 108\\7x+( 171 - 14x)=108\\-7x=-63\\x=9$

Since x = 9, the angle "14x + 9" would be:

14(9) + 9 = 135

Hence Angle 1 would be:

$\angle 1 + 14x + 9 = 180\\\angle 1 + 135 = 180\\\angle 1 = 45$

6 0

2 years ago

In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th

WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ; 10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, $\frac{dx}{dt}$ = $1,000

Now,

a) computers per household are

since,

mean income of $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e $\frac{dq}{dt}$

$\frac{dq}{dt}$ = $\frac{d(0.3458 ln x - 3.045)}{dt}$

or

$\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0$

on substituting the values, we get

$\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000$

or

= 0.01153 computers

6 0

3 years ago