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jeka94
3 years ago
9

Determine two numbers that have a product of 40 and a sum of 13. help:(

Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0

Hey there!

First, let's list the factors of 40:

1 x 40, 2 x 20, 4 x 10, 5 x 8,

We need to figure out which pair of factors has a sum of 13.

1 + 40 = 41 --> Nope

2 + 20 = 22 --> Nope

4 + 10 = 14 --> Nope

5 + 8 = 13 --> Yes!

The two numbers that have a product of 40 and a sum of 13 are 5 and 8.

Hope this helps!

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Alenkinab [10]

PEMDAS

P is parenthesis

E exponents

m multiply

d division

a addition

s substraction

to help you say the phrase "Please Excuse My Dear Aunt Susan" 10 times!

5 0
3 years ago
Read 2 more answers
Jill gets a base pay of $1500 per month. She also earns a commission of 8% of her total sales. What are Jill's earnings for a mo
mart [117]

Answer:

$4060.

Step-by-step explanation:

We have been given that Jill gets a base pay of $1500 per month. She also earns a commission of 8% of her total sales. We are asked to find Jill's earnings for a month in which she has sales of $32,000.

Jill's earnings for the month would be base salary pus 8% of $32,000.

\text{Jill's total earnings for the month}=\$1500+\$32,000\times \frac{8}{100}

\text{Jill's total earnings for the month}=\$1500+\$320\times8

\text{Jill's total earnings for the month}=\$1500+\$2560

\text{Jill's total earnings for the month}=\$4060

Therefore, the Jill's earnings for the given month would be $4060.

7 0
4 years ago
HELP!! NEED TODAY!!<br><br> Find the value of x in each case.
Juliette [100K]

Answer:

x = 14

Step-by-step explanation:

∠ DCA and ∠ BCF are adjacent angles and sum to 180° , then

∠ DCA = 180° - 124° = 56°

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

6x is an exterior angle , then

6x = 2x + 56 ( subtract 2x from both sides )

4x = 56 ( divide both sides by 4 )

x = 14

7 0
3 years ago
Determine the equations of the vertical and horizontal asymptotes if any for h(x)=(x+1)^2/x^2-1
shepuryov [24]

ANSWER

Vertical asymptote:

x=1

Horizontal asymptote:

y=1

EXPLANATION

The given rational function is

h(x) =  \frac{ {(x + 1)}^{2} }{ {x}^{2} - 1 }

h(x) =  \frac{ {(x + 1)}^{2} }{ ({x}  - 1)(x + 1)}

h(x) =  \frac{ (x + 1)(x + 1) }{ ({x}  - 1)(x + 1)}

h(x) =  \frac{ x + 1}{ {x}  - 1}

The vertical asymptote occurs at

{x} - 1 = 0

x = 1

The vertical asymptotes is x=1

The degree of the numerator is the same as the degree of the denominator.

The horizontal asymptote of such rational function is found by expressing the coefficient of the leading term in the numerator over that of the denominator.

y =  \frac{1}{1}

y=1

8 0
3 years ago
Solve the following system of equations by using the method of your choice
topjm [15]

Answer:

(x, y) =(-6,4)

Step-by-step explanation:

3x-y=-28

-5x-4y=-10

y=3x+28

-5x-4(3x+28)=-10

y=3x+28

-5x-12x-112=-10

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-17x=-10+112

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y=3x+28

x=-6

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x=-6

y=-24+28

x=-6

y=4

x=-6

(x,y)=(-6,4)

6 0
3 years ago
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