The sum of the given series can be found by simplification of the number
of terms in the series.
- A is approximately <u>2020.022</u>
Reasons:
The given sequence is presented as follows;
A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021
Therefore;
The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;
Therefore, for the last term we have;
2 × 2043231 = n² + 3·n + 2
Which gives;
n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0
Which gives, the number of terms, n = 2020
Which gives;
Learn more about the sum of a series here:
brainly.com/question/190295
Answer: A & C
Step-by-step explanation:
Answer:
63
Step-by-step explanation:
John's percentage:
36 and 48 have a common factor of 12 so divide both of them by 12.
36/12= 3 and 48/12=4 therefore
so 36/48= 3/4 which is 75% but we don't need to focus on the percent.
Don's no. of shirts:
we know Don has 84 shirts so we say
3/4 of 84= no. of shirts that Don put in his closet
84/4=21 21x3=63
Don put 63 shirts in his closet.
Hope that helped! Anymore questions just ask! :)
Answer:
B i think
Step-by-step explanation:
you are supposed to multiply the 80*.3 and that will give you 24 and subtract from 80 but im not sure
sorry if i got this wrong
Answer:
Only option d is not true
Step-by-step explanation:
Given are four statements about standard errors and we have to find which is not true.
A. The standard error measures, roughly, the average difference between the statistic and the population parameter.
-- True because population parameter is mean and the statistic are the items. Hence the differences average would be std error.
B. The standard error is the estimated standard deviation of the sampling distribution for the statistic.
-- True the sample statistic follows a distribution with standard error as std deviation
C. The standard error can never be a negative number. -- True because we consider only positive square root of variance as std error
D. The standard error increases as the sample size(s) increases
-- False. Std error is inversely proportional to square root of n. So when n decreases std error increases
