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Paladinen [302]
4 years ago
13

L 3.2.3 Quiz: Friction

Physics
1 answer:
MAVERICK [17]4 years ago
6 0

Answer:

the higher the value of the coefficient of friction the MORE the resistance to sliding . 

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Imagine you had a bar of gold and decided to cut in half. You repeated this process until eventually you could no longer cut the
nydimaria [60]

This would prove that gold is an <em>element</em>.  No matter how far down you
examine it, you never find any particles of anything except gold.

An example of a different case is salt. 
-- Imagine you had a block of salt and decided to cut it in half.
-- If you repeated this process, then eventually, at some point, you'd have
a tiny particle of salt in front of you, just like before.  BUT ...
-- Just as you were getting ready to cut this one in half, you'd notice that this
particle of salt is different.  It's one atom of sodium stuck to one atom of chlorine,
and if you cut it in half, you would not have ANY salt.   <span />

This would prove that salt is a <em><u>compound</u></em>, made of atoms of two or more elements.

3 0
4 years ago
Read 2 more answers
A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19s lat
victus00 [196]

Answer / Explanation

It is worthy to note that the question is incomplete. There is a part of the question that gave us the vale of V₀.

So for proper understanding, the two parts of the question will be highlighted.

A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19s later. You may ignore air resistance.

a) What must the height of the building be for both balls to reach the ground at the same time if (i) V₀ is 6.0 m/s and (ii) V₀ is 9.5 m/s?

b) If Vo is greater than some value Vmax, a value of h does not exist that allows both balls to hit the ground at the same time.  

Solve for Vmax

Step Process

a)  Where h = 1/2g [ (1/2g - V₀)² ] / [(g - V₀)²]

Where V₀ = 6m/s,

We have,

           h = 4.9 [ ( 4.9 - 6)²] / [( 9.8 - 6)²]

                 = 0.411 m

Where V₀ = 9.5m/s

We have,

     h = 4.9 [ ( 4.9 - 9.5)²] / [( 9.8 - 9.5)²]

                 = 1152 m

b)  From the expression above, we got to realise that h is a function of V₀, therefore, the denominator can not be zero.

Consequentially, as V₀ approaches 9.8m/s, h approaches infinity.

Therefore Vₙ = V₀max = 9.8 m/s

4 0
3 years ago
You are in charge of a cannon that exerts a force 11500 N on a cannon ball while the ball is in the barrel of the cannon. The le
IRISSAK [1]

Answer:

m = 7.48 kg

Explanation:

force (f) = 11,500 N

length of barrel (s) = 1.7 m

angle above the ground = 49.3 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

initial velocity (u) = 0 m/s

final velocity (v) = 72.3 m/s

mass (m) = ?

force = mass (m) x acceleration (a)

acceleration (a) = force / mass (m)

acceleration (a) = 11500 / m

applying the equation of motion v^{2} = u^{2} + 2as , we can get the mass

72.3^{2} = 0^{2} + (2 x \frac{11500}{m} x 1.7 )

5227.3 = 0 + \frac{39100}{m}

m =  \frac{39100}{5227.3}

m = 7.48 kg

5 0
3 years ago
Kara started a new exercise program. Kara’s sister works out with her on a regular basis and even talks to Kara about her progre
uysha [10]
A. goal setter or C. support system
4 0
3 years ago
Read 2 more answers
What is the potential energy of a 3 kilogram-ball that is on the ground?
Aleks [24]
The answer is 0
potential energy= mass• gravity (9.8m/s)• height.
Your mass 3kg. I believe your need to convert this to grams (3000g) and then multiply by 9.8. Since your height is 0 because the ball is on the ground then your potential energy is 0
3 0
3 years ago
Read 2 more answers
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