The process by which the gene in the nucleotide suddenly changes its position is called.

Physics

1 answer:

Ksenya-84 [330]1 year ago

8 0

Mutation is the process by which the gene in the nucleotide suddenly changes its position

Any change in the structure of a gen or in the usual DNA sequence of a cell is called mutation. It can be caused by mistakes during cell division when the DNA is copied or by the exposure to DNA damaging agents in the environment like UV light or cigarette smoke, and may be transmitted to subsequent generations.

A mutation is a permanent alteration of the nucleotide sequence of an organism, virus or other genetic elements.

There are three types of mutations:

Base substitutions
Deletions
Insertions

The Deoxyribonucleic acid, also called DNA, is the hereditary material that carries genetic information for the development and functioning of humans and almost all other organisms. DNA is made of nucleotides.

Learn more about DNA at brainly.com/question/16099437

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A box sits at rest on a rough 33° inclined plane. Draw the free-body diagram, showing all the forces

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(a) The free body of all the forces include, frictional force, weight of the box acting perpendicular and another acting parallel to the plane.

(b) When the box is sliding down, the frictional force acts towards the right.

<h3>Free body diagram</h3>

The free body diagram of all the forces on the box is obtained by noting the upward force and downward forces on the box as shown below;

/ W2

Ф → Ff

↓W1

where;

Ff is the frictional force resisting the down motion of the box
W1 is the perpendicular component of the box weight = Wcos(33)
W2 is the parallel component of the box weight = Wsin(33)

(b) When the box is sliding down, the frictional force acts towards the right.

Learn more about free body diagram of inclined objects here: brainly.com/question/4176810

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2 years ago

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I'm pretty sure it's D. The stars don't influence the moon's phases.

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3 years ago

Calculate the average drift speed of electrons traveling through a copper wire with a crosssectional area of 80 mm2 when carryin

Vedmedyk [2.9K]

Answer:

The correct answer is $2.8*10^{-5}ms^{-1}$

Explanation:

The formula for the electron drift speed is given as follows,

$u=I/nAq$

where n is the number of of electrons per unit m³, q is the charge on an electron and A is the cross-sectional area of the copper wire and I is the current. We see that we already have A , q and I. The only thing left to calculate is the electron density n that is the number of electrons per unit volume.

Using the information provided in the question we can see that the number of moles of copper atoms in a cm³ of volume of the conductor is $8.93/63.5 molcm^{-3}$ . Converting this number to m³ using very elementary unit conversion we get $140384molm^{-3}$ . If we multiply this number by the Avagardo number which is the number of atoms per mol of any gas , we get the number of atoms per m³ which in this case is equal to the number of electron per m³ because one electron per atom of copper contribute to the current. So we get,

$n=140384*6.02*10^{23} = 8.45*10^{28}electrons.m^{-3}$

if we convert the area from mm³ to m³ we get $A=80*10^{-6}m^{2}$ .So now that we have n, we plug in all the values of A ,I ,q and n into the main equation to obtain,