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3 years ago

100 POINTS!!! :D

Physics

2 answers:

charle [14.2K]3 years ago

4 0

Explanation:

... in every interaction, there is a pair of forces acting on the two interacting objects. The size of the force on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.

amid [387]3 years ago

4 0

That’s called collision
In every interaction, there is a pair of forces acting on the two interacting objects. The size of the force on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.

Hope this helps :D

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A laser beam is incident on two slits with a separation of 0.195 mm, and a screen is placed 5.30 m from the slits. If the bright

kumpel [21]

Answer:

λ = 596 nm.

Explanation:

Fringe width = λ D / d

λ is wave length , D is screen distance and d is slit separation.

Putting the values

1.62 x 10⁻² =( λ x 5.3 ) / .195 x 10⁻³

$\lambda=\frac{1.62\times10^{-2}\times195\times10^{-6}}{5.3}$

λ = 596 nm.

8 0

3 years ago

Which of the following is an example of a wedge? a. a mop b. an axe c. a wheel d. a door knob

WITCHER [35]

The answer is ( b. an axe )

3 0

3 years ago

A red train traveling at 72 km/hr and a green train traveling at 144 km/hr are headed toward one another along a straight level

Temka [501]

First, convert all the km/hr into m/s

You will get that
initial speed = 20 m/s
Initial speed of Green train = 40 m/s
Initial separation = 950 m
Velocity of approach = 20 - -40 = 60 m/s
relative acceleration = -4 m/s^2

v = u + at
0 = 60 - 4t

t = 15s

s = ut + 1/2 *at * t

s = 60 * 15 - 1/2 *4 * 225
s = 900 - 450

Separation when they stop = 450 m

hope this helps

5 0

3 years ago

Mt. Asama, Japan, is an active volcano. In 2009, an eruption threw solid volcanic rocks that landed 1 km horizontally from the c

Nata [24]

Answer:

a) 69.3 m/s

b) 18.84 s

Explanation:

Let the initial velocity = u

The vertical and horizontal components of the velocity is given by uᵧ and uₓ respectively

uᵧ = u sin 40° = 0.6428 u

uₓ = u cos 40° = 0.766 u

We're given that the horizontal distance travelled by the projectile rock (Range) = 1 km = 1000 m

The range of a projectile motion is given as

R = uₓt

where t = total time of flight

1000 = 0.766 ut

ut = 1305.5

The vertical distance travelled by the projectile rocks,

y = uᵧ t - (1/2)gt²

y = - 900 m (900 m below the crater's level)

-900 = 0.6428 ut - 4.9t²

Recall, ut = 1305.5

-900 = 0.6428(1305.5) - 4.9 t²

4.9t² = 839.1754 + 900

4.9t² = 1739.1754

t = 18.84 s

Recall again, ut = 1305.5

u = 1305.5/18.84 = 69.3 m/s

7 0

3 years ago

Two long, straight wires both carry current to the right, are parallel, and are 25 cm apart. Wire one carries a current of 2.0 A

Artemon [7]

Answer:

x = 7.14 meters

Explanation:

It is given that,

Current in wire 1, $I_1=2\ A$

Current in wire 2, $I_2=5\ A$

Distance between parallel wires, r = 25 cm

Let at P point the net magnetic field equal to 0. The magnetic field at a point midway between the is given by :

$B=\dfrac{\mu_oI}{2\pi r}$

Let the distance is x from wire 1. So,

$\dfrac{I_1}{r}=\dfrac{I_2}{(0.25-r)}$

$\dfrac{2}{r}=\dfrac{5}{(25-r)}$

$x=\dfrac{50}{7}\ m$

x = 7.14 meters

So, the magnetic field will be 0 at a distance of 7.14 meters from wire 1. Hence, this is the required solution.

6 0

3 years ago