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Damm [24]
3 years ago
5

The type of energy transferred by a wave in a medium is______ energy

Physics
1 answer:
12345 [234]3 years ago
7 0

Answer:

kinetic energy

Explanation:

When particles become part of a wave, they start to move up or down. This means that kinetic energy (energy of movement) has been transferred to them.

well, it also depends on the type of medium you're talking about. But, basically kinetic energy is transferred

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When astronauts travel to the moon, their bodies experience a lower gravitational pull than on Earth. Which type of pull are the
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They are experiencing the pull of leaving the atmosphere

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If a boy (m = 25 kg) at rest on skates is pushed by another boy who exerts a force of 500 N on him and if the first boy's final
Bond [772]

Answer:

1 second

Explanation:

The impulse exerted on the boy is equal to its change of momentum:

I = \Delta p\\F \Delta t = m \Delta v

where

F = 500 N is the push on the boy

\Delta t is the contact time

m = 25 kg is the mass of the boy

\Delta v = 20 m/s is the change in velocity of the boy

Solving the formula for the contact time, we find

\Delta t=\frac{m\Delta v}{F}=\frac{(25 kg)(20 m/s)}{500 N}=1 s

7 0
3 years ago
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larisa [96]

Answer:

wow i have know idea

Explanation:

5 0
3 years ago
Which of the following is the best definition of the term pseudopsychology?
blagie [28]
Can you give us the options…?
3 0
3 years ago
a 1500 kg car accelerates uniformly from rest to 10.0 meters per secound in 3.0 secound .what is the work done on the car in thi
zubka84 [21]

Answer:

The work done on the car is, W = 75,000 J

The power delivered by the engine, P = 25,000 watts

Explanation:

Given,

The mass of the car, m = 1500 Kg

The initial velocity of the car, u = 0

The final velocity of the car, v = 10 m

The time duration of the travel, t = 3 s

Using the first equation of motion

                     v = u + at

                     a = (v - u) / t

Substituting the given values in the above equation

                    a = (10 - 0) / 3

                       = 3.33 m/s²

Using the second equations of motion

                      s = ut + 1/2 at²

                         = 0 + 0.5 x 3.33 x 3²

                         = 15 m

The force exerted by the car

                         F = m x a

                            = 1500 Kg x 3.33 m/s²

                            = 5000 N

The work done by the car,

                          W = F x S

                               = 5000 N x 15 m

                               = 75,000 J

Hence, the work done on the car is, W = 75,000 J

The power delivered by the engine,

                            P = W / t

                                = 75,000 J / 3 s

                                 = 25,000 watts

The power delivered by the engine, P = 25,000 watts

5 0
3 years ago
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