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lakkis [162]
3 years ago
5

What is the reactance of a capacitor at a 8.0 μF frequency of 56.0 Hz?

Physics
1 answer:
il63 [147K]3 years ago
8 0

Answer:

35.55 ohm

Explanation:

C = 80 micro farad

F = 56 hertz

Reactance

Xc = 1 / (2 × pi × F × C)

Xc = 1 / ( 2 × 3.14 × 56 × 80 × 10^-6)

Xc = 35.55 ohm

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Three joules of work is needed to shift 10 C of charge from one place to another. The potential difference between the places is
dimaraw [331]

Answer:

The potential difference between the places is 0.3 V.

∴ 1st option i.e. 0.3V is the correct option.

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To determine

We need to determine the potential difference V between the places.

The potential difference between the two points can be determined using the formula

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or

\:V\:=\:\frac{W}{q}

substituting W = 3 and q = 10 in the formula

V=\frac{3}{10}

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Therefore, the potential difference between the places is 0.3 V.

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