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3 years ago

What is the reactance of a capacitor at a 8.0 Î¼F frequency of 56.0 Hz?

Physics

1 answer:

il63 [147K]3 years ago

8 0

Answer:

35.55 ohm

Explanation:

C = 80 micro farad

F = 56 hertz

Reactance

Xc = 1 / (2 × pi × F × C)

Xc = 1 / ( 2 × 3.14 × 56 × 80 × 10^-6)

Xc = 35.55 ohm

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The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5

KiRa [710]

Answer:

0.68 s

Explanation:

We are given that

Initial velocity of box= $u=13m/s$

Final velocity of box=v=11.5 m/s

Distance=d=8.5 m

We have to find the time taken by box to slow by this amount.

We know that

$v^2-u^2=2as$

Substitute the values

$(11.5)^2-(13)^2=2a(8.5)$

$132.25-169=17a$

$-36.75=17a$

$a=\frac{-36.75}{17}=-2.2m/s^2$

We know that

Acceleration= $a=\frac{v-u}{t}$

Substitute the values

$-2.2=\frac{11.5-13}{t}$

$-2.2=\frac{-1.5}{t}$

$t=\frac{1.5}{2.2}=0.68 s$

Hence, the time taken by box to slow by this amount=0.68 s

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3 years ago

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zlopas [31]

Answer:

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