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3 years ago

Simply 18/72 ..............................

Mathematics

1 answer:

marusya05 [52]3 years ago

7 0

Answer: (18/72) simplified as a fraction is (1/4)

Step-by-step explanation: I know this is the answer because (1/4) x 18 = (18/72)

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GUYS PLEASE HELP WITH MY MWTH TEST

OleMash [197]

Answer:

sinθ = 5/13

cosθ = 12/13

tanθ = 5/12

Step-by-step explanation:

Get the remaining side(hypotenuse) first,

hypotenuse^2 = 12^2 + 5^2 (Pyth. theorem)

hypotenuse = 13

sinθ = 5/13

cosθ = 12/13

tanθ = 5/12

6 0

3 years ago

Can someone please simplify these using product notation?

Contact [7]

A. 3a b. a^3 c. 4x d. 3pq e. 7^ef f. zxy^1

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3 years ago

A test preparation claims that more than 50% of the students who take their test prep course improve their scores by at least 1

satela [25.4K]

Answer:

Step-by-step explanation:

Corresponding scores before and after taking the course form matched pairs.

The data for the test are the differences between the scores before and after taking the course.

μd = scores before taking the course minus scores before taking the course.

a) For the null hypothesis

H0: μd ≥ 0

For the alternative hypothesis

H1: μd < 0

b) We would assume a significance level of 0.05. The P-value from the test is 0.65. The p value is high. It increases the possibility of accepting the null hypothesis.

Since alpha, 0.05 < than the p value, 0.65, then we would fail to reject the null hypothesis. Therefore, it does not provide enough evidence that scores after the course are greater than the scores before the course.

c) The mean difference for the sample scores is greater than or equal to zero

3 0

3 years ago

Solve the unknown viable 7c/12 + 5c/16=15/48 +c

Mashutka [201]

deconstructing
48 : 2 = 24
24 : 2 = 12
12 :2 = 6
6 : 2 = 3
3 : 3 = 1
2 * 2 * 2 * 2 * 3 = 48
...................................
16 : 2 = 8
8 : 2 = 4
4 : 2 = 2
2 : 2 = 1
2 * 2* 2 * 2 = 16
..................................
12 : 2 = 6 $\frac{7c}{12} + \frac{5c}{16} = \frac{15}{48} + c \\ \\ \frac{7c*4}{12*4} + \frac{5c*3}{16*3} - \frac{15}{48} = c \\ \\ \frac{28c + 15c}{48} - \frac{15}{48} = c \\ \\ 48c = 43c - 15 \\ \\ 48c - 43c = -15 \\ \\ 5c =- 15 \\ \\ c = -3
$ 
6 : 2 = 3
3 : 3 = 1
common denominator 48

5 0

3 years ago

Find the zeros (roots) of the following equations. f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0

Talja [164]

Hi,
$f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\
=2-9+12-12+10-3\\
=0\\

f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\


g(x)=2x^4-7x^3+5x^2-7x+3\\

g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\
=162-189+45-21+3\\
=0\\

g(x)=(x-3)(2x^3-x^2+2x-1)\\

h(x)=2x^3-x^2+2x-1\\

h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\
=0\\

h(x)=(2x-1)(x^2+1)\\


f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\


$
Roots are 1,3,0.5,i,-i.

8 0

3 years ago