Seeing the graph from desmos.com, we know there is only one place where the graph will go up then down, or down then up given that the maximum exponent of x is it squared. That place, as seen, is -0.375 for the minimum as it goes down then up. There's no maximum in sight :(
Suppose 
is another solution. Then
Substituting these derivatives into the ODE gives
Let 
, so that
Then the ODE becomes
and we can condense the left hand side as a derivative of a product,
![\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E5u%5D%3D0)
Integrate both sides with respect to 
:
![\displaystyle\int\frac{\mathrm d}{\mathrm dx}[x^5u]\,\mathrm dx=C](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%5Cfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E5u%5D%5C%2C%5Cmathrm%20dx%3DC)
Solve for 
:
Solve for 
:
So another linearly independent solution is 
.
Answer:
y = 7/8x + 7
Step-by-step explanation:
7x- 8y = -56
-7x -7x
-8y = -7x - 56
y = 7/8x + 7
width= 8
Length= 15
(8x15= 120 and 8 is 7 less than 15)
I would say for every 1 brownie, there are 5 cookies.
