We can set up 2 equations given the information.
Let the price of advance ticket be represented by A and same day ticket by S
A + S = 50
20A + 40S = 1700
Solve for A in the first equation by subtracting S on both sides.
U will get A = 50 - S
Now substitute 50 - S for A in the second equation.
20 (50 - S) + 40S = 1700
1000 - 20S + 40S = 1700
20S = 700
S = 35
Same day ticket costs $35 and advance ticket costs $15
Answer:
A
Step-by-step explanation:
To sovle this we must combine the numbers togther and the variables togther.
We have:
8c+6-3c-2
Lets take out the c's and combine them:
8c -3c
=
5c
Now lets take out the numbers:
6-2
=
4
Now lets put these back together and we get the expression:
5c+4
This looks like A.
Hope this helps! :D
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Answer:
k
2
+
k
+
1
Step By Step:
Cancel the common factor.
Then.
k
2
+
k
+1
by 1
Gets you k2+k+1
