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professor190 [17]
3 years ago
15

Consider a slightly modified Monty Hall problem: Suppose you're on a game show, and you're given the choice of three doors: Behi

nd one door is a car; behind the others, wildcats (placed uniformly at random). The two wildcats are called Alice and Bill, say. You pick a door, say No. 1 [but the door is not opened]. The host, who knows what's behind the doors, must open one of the two remaining doors to reveal a wildcat. In particular, if the host had a choice between the two wildcats, the host will show you Bill with probability b. Find the probability that the car is behind the door you initially chose, given that the wildcat revealed to you is Bill. Remember to write down the sample space and associated probabilities.
Mathematics
1 answer:
Ber [7]3 years ago
8 0

Answer: that’s tuff

Step-by-step explanation:

Omg

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Suppose the population of a certain city is 5289 thousand. It is expected to decrease to 4530 thousand in 50 years. Find the per
Tcecarenko [31]

Answer:

14.4% decrease

Step-by-step explanation:

Here is the formula for finding the percentage of decrease:

(starting value - final value) / starting value * 100.

So for your question,

\frac{5289-4530}{5289} =.0144\\.0144 * 100 = 14.4\\/

There was a 14.4% decrease within 50 years.

5 0
3 years ago
If there are x teams in a sports​ league, and all the teams play each other​ twice, a total of​ n(x) games are​ played, where ​n
EleoNora [17]
1.
Consider a group of n objects. Assume we want to form groups of r, from these n objects.

There are in total C(n, r)= \frac{n!}{r!(n-r)!} many ways of doing so.

where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r

2.

C(x, 2) is the total number of pairs out of x objects, that we can form.

so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.

The total number of games is:

n(x)=2*C(x, 2) = 2*  \frac{x!}{2!(x-2)!}= \frac{x!}{(x-2)!}= \frac{x(x-1)(x-2)!}{(x-2)!}=x(x-1)= x^{2} -x

Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.


Answer: x^{2} -x

6 0
3 years ago
Please help me!!!! Help me find the dimensions. :(
Gnom [1K]
The volume, surface area and the ratios of the SA to volume will be as follows:
Volume=πr²h
Area=2πr²+πdh
Ratio of SA to volume=Area/volume
π=3.14
Thus using the above formula:

1.
a]
Radius: 3 inches
Height: 2 inches
Volume=πr²h
volume=π×3²×2=56.52 in³

b]
Area=2πr²+πdh
2×π×3²+π×2×3×2
=56.55+37.68
=94.23 in²

c]
Ratio=area/volume
=94.23/56.52
=1.6672


1. 
Radius: 2 inches
Height: 9 inches

a]
V=πr²h
V=3.14*2^2*9
V=113.04 in³

b] 
Area=2πr²+πdh
=2*3.14*2^2+3.14*2*2*9
=25.12+113.04
=138.16 in²

c]
Ratio=area/volume
=138.16/113.04
=11/9

3.
Diameter=4 inches
Height= 9 inches

a]
V=πr²h
V=3.14×2²×9
V=113.04

b]
Area=2πr²+πdh
=2*3.14*2^2+3.14*4*9
=25.12+113.04
=138.16 in²

c]
Ratio=area/volume
=138.16/113.04
=11/9

4]
Diameter: 6 inches
Height: 4 inches

a]
Volume=πr²h
=3.14×3²×4
=113.04 in³

b]
Area=2πr²+πdh
=2×3.14×3²+3.14×6×4
=56.52+75.36
=131.88 in²

c] Ratio
131.88/113.04
=7/6

1. For the surface area to volume to be small it means that the area is smaller than the volume, for surface area to volume  be larger it means that the surface area is larger than the volume. It is more economical for the surface area to volume to be small because it will mean that small amount of materials make cans with large volume. This means cost of production is cheaper.

2. To evaluate this process let's use one of the dimensions:
Radius: 3 inches
Height: 2 inches:

i. add radius and height:
3+2=5 inches
ii. Multiply radius and height:
3×2=6
iii. Dividing the result from step 1 by the result in step 2:
5/6

iv. Multiply the result from step 3 by 2:
5/6×6
=5
This result does not seem to add up to the result in our earlier ratio. Thus we conclude that Khianna was wrong. This method can't work with 3-D figures.


7 0
4 years ago
Use the Well-Ordering Principle to prove that given a > 0, a^n > 0 for every positive integer n
pishuonlain [190]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given value:

\to x > 0

\to S= { n\varepsilon N : x^n \leq 0  } \\\\  s \neq \phi \\\\ \to x^n \leq 0\\

\to x^{n-1} x\leq 0\\\\ \to x>0  = x^{n-1} \leq 0 \\\\\to n-1 \varepsilon  s  \\  \ \ _{where} \ \  n-1 < n \\\\\to s= \phi  \\\\\to \hence  x^n > 0 \\

8 0
4 years ago
X = −6, which inequality is true? A. −5 − 3x &gt; 10 B. −3 − 5x 13 D. 2 − x &lt; −3
Iteru [2.4K]

jdkdjdj:

Step-by-step explanation:jfjdjdjfjfnfnfmdk heyyy

8 0
3 years ago
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