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Ilia_Sergeevich [38]
3 years ago
6

Approximately 18% of the calls to an airline reservation phone line result in a reservation being made. (a) suppose that an oper

ator handles 15 calls. what is the probability that none of the 15 calls result in a reservation?
Mathematics
1 answer:
MrRissso [65]3 years ago
3 0
Answer: The probability that none of the calls would result in a reservation would be 0.72%.

Since there is an 18% chance that there would be a reservation, then there is a 72% chance that there is not a reservation.

Our goal is to determine the likelihood that there are no calls. Or that the 72% chance event happens 15 times.

We can use the following expression to find that repeated probability.

(0.72)^15 = 0.0072 or 0.72%
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The larger of two number is 5 times the smaller. The difference between them is 36
Anestetic [448]
X = larger number, y = smaller number

x = 5y
x - y = 36

5y - y = 36
4y = 36
y = 36/4
y = 9

x = 5y
x = 5(9)
x = 45

ur numbers are 45 and 9 <==

4 0
3 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
1 year ago
HELP ME PLEASE THANKS
Anika [276]
The ^3 and ^2 are exponents sorry I don’t think you can type exponents on a keyboard, 6x^3+22x^2+3x-6
3 0
3 years ago
HELP 50 POINTS IF U ANSWER
Vaselesa [24]

Answer:

Draw an open circle at 6.

Shade all numbers less than 6.

Shade all numbers to the left of 6.

Step-by-step explanation:

I hope this helps!

5 0
3 years ago
vending machine dispenses hot chocolate or coffee. Service time is 30 seconds per cup and is constant. Customers arrive at a mea
Zolol [24]

Answer:

0.667 ;

0.667 customers ;

0.0166708 hour ;

1.334 customers

Step-by-step explanation:

Given that:

Service time (μ) = 30 seconds ; 2 customers per minute ; 2 * 60 = 120 customers per hour

Arrival time, λ = 80 customers per hour

a.) percentage of time machine is busy (p) ; Utilization factor :

P = λ/ μ = 80 / 120 = 0.667

b.) average number of customers waiting in line Li = p² / 2(1-p)

= 0.667² / 2(1-0.667) = 0.667 customers

c) Average time customer spend in the system = Li/λ + 1/μ

= (0.667 / 80) + (1 / 120)

0.0083375 + 0.0083333

= 0.0166708 hour

= 0.0166708 * 60 = 1.00025 minutes

D) average number in the system ;

Li + p

= 0.667 + 0.667 = 1.334 customers

3 0
3 years ago
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