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MrMuchimi
3 years ago
15

Charles would like to visit a specific page on the World Wide Web. How should he do it? Enter the address in a search engine cli

ck on the address bar, type the URL, and press Enter click on the title bar, type the URL, and press the space bar open the display window, enter the ip address, and press Enter
Computers and Technology
2 answers:
son4ous [18]3 years ago
4 0

Answer:

type the URL, and press Enter click on the title bar

Explanation:

mihalych1998 [28]3 years ago
4 0

Type the URL and press enter on the keyboard.

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Create a recursive method, a method that calls itself, that returns the number of vowels that appear in any string given. Keep i
kvv77 [185]
<h2>Answer:</h2>

//Define the method as noOfVowels

   //Let it receive the string to be checked as argument

   public static int noOfVowels(String string){

   

       //Check the length of the string

       

       //If it is less than 1, then it is an empty string

       //Hence return 0

       if(string.length() < 1){    

           return 0;

       }

       

       //Else,

       else{

           //get the character at the first position in the string

           //and convert it to a lower case

           char x = string.toLowerCase().charAt(0);

           //Check if the character is a vowel

           if (x == 'a' || x == 'e' || x == 'i' || x == 'o' || x == 'u'){

               //if it is a vowel, add 1 to a recall of the method.

               //But this time, call the method with  

               //the string excluding the first character.

               //i.e the substring of the string starting at index 1 rather than 0

               return 1 + noOfVowels(string.substring(1));

           }

           

           else {

               //If it is not a vowel, just recall the method with

               //the string excluding the first character

               //i.e the substring of the string starting at index 1 rather than 0

               return noOfVowels(string.substring(1));

           }

       }

   }

   

<h2>Explanation:</h2><h2></h2>

The code has been written in Java and it contains comments explaining every part of the code. Please go through the comments carefully.

The actual lines of code have been written in bold face to distinguish them from comments.

The code is re-written without comments as follows;

   public static int noOfVowels(String string){

   

       if(string.length() < 1){    

           return 0;

       }

       

       else{

           char x = string.toLowerCase().charAt(0);

           if (x == 'a' || x == 'e' || x == 'i' || x == 'o' || x == 'u'){

               return 1 + noOfVowels(string.substring(1));

           }

           

           else{

               return noOfVowels(string.substring(1));

           }

       }

   }

   

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How to transfer photos from iphone to computer
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If you’re using a Windows computer, the best way to transfer photos from your iPhone to your computer is via USB cable.
First, plug your phone into your computer using the phone’s USB Cable. The Photo app should launch automatically then click the Import button. Check to select the photos you wish to transfer. Once you checked all the photos you wish to transfer, click on Continue. Click Import to start the transfer.
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Networking capabilities of a computer
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Int[] myArray1= new int[24]; int[] myArray2= new int[10]; float[] myArray3= new float[8]; int index1, index =0 for(int index1 =0
anastassius [24]

Answer:

The value of myArray2[index2] when index1 = 12 is 30

Explanation:

In the source code, the formula for myArray2[index2] is;

   myArray2[index2] = index2 + index3 + myArray1[index1],

   myArray1[index1] = index1 * 2,

   index2 = index % 10 (equal to the remainder) and

   index3  = index % 8

When index1 increases to 12 in the for-loop statement, the "myArray1[index1]" is equal to 24, index2 is equal to 2 and index3 is 4. The total sum is equal to 30 and assigned to "myArray2[index2]".

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No I have not had that do that to me before It has always loaded my ads and sent me right back to the answer

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