<u>Answer:</u> The molality of magnesium chloride is 1.58 m
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute (magnesium chloride) = 75.0
= Molar mass of solute (magnesium chloride) = 95.21 g/mol
= Mass of solvent = 500.0 g
Putting values in above equation, we get:
Hence, the molality of magnesium chloride is 1.58 m
Answer:
See below!
Explanation:
For the chemical formula, you need to have enough of each atom so that the charge is zero.
Aluminum has a +3 charge, and fluorine has a -1 charge. Since the charge has to be zero, you need three fluorines, giving you AlF₃.
Barium has a +2 charge, and oxygen has a -2 charge. Since the charges are equal in magnitude but opposite in sign, you only need one of each atom giving you BaO.
The name of the ionic compound will be the metal and then the nonmetal. When putting the nonmetal in, change the ending to "-ide". For example "chlorine" would be "chloride.
CaCl₂ ==> calcium chloride
Ga₂S₃ ==> gallium sulfide
K₃N ==> potassium nitride
AlF₃ ==> aluminum fluoride
BaO ==> barium oxide
Answer:
A) increasing the pressure
Explanation:
Given the exothermic reaction:
2SO₂(g) + O₂(g) ↔ 2SO₃(g)
the question asks what will make the number of moles of SO₃(g) to increase.
When an equilibrium is disturbed, the system will shift in order to counteract the change (see <em>Le Chatelier's Principle</em>) So <em>when the pressure is increased in a reaction involving gases, the equilibrium will shift trying to decrease the number of moles </em>(because pressure is produced by molecules hitting the container), that is in this case it will shift towards the right side, towards the production of SO₃, thus increasing the number of moles of SO₃.
The number of moles in the right side is 2 and the number of moles in the left side is 3.
Answer:
The answer is 7 (seven)
Explanation:
Fluorine has seven of eight possible electrons in its outermost energy level, which is energy level II.
MgCl₂ & PbSO₄ is the correct product for the given double replacement reaction.
<h3>What is double displacement reaction?</h3>
In the double displacement reaction displacement of two substrate will take place among two reactants and formation of products takes place.
In the question, PbCl₂ reacts with MgSO₄ and displacement between the cations takes place and formation of MgCl₂ and insoluble precipitate PbSO₄ is formed.
Given reaction is represented as:
PbCl₂ + MgSO₄ → MgCl₂ + PbSO₄
According to the activity series, reactivity of Magnesium is more as compared to the lead atom. So lead is displaced by the magnesium atom and form the above given products.
Hence, option (3) is correct i.e. MgCl₂ & PbSO₄.
To know more about double displacement reaction, visit the below link:
brainly.com/question/26413416