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lana [24]
3 years ago
12

Calculate the molarity of hydroxide ion in an aqueous solution that has a poh of 5.00

Chemistry
1 answer:
Simora [160]3 years ago
4 0

Answer:

1.00 x 10^-5 M

Explanation:

pOH=-log[OH^-]

so

[OH^-]=10^(-pOH)

=10^-5

=1.00 x 10^-5 M

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What would you predict to be the valence number and oxidation number of tin?
murzikaleks [220]

Answer:

Tin exists in two oxidation states, +4 and +2. Elemental tin is readily oxidized to the dipositive ion in acidic solution, but this Sn2+ ion is converted to the Sn4+ ion by many mild oxidizing agents, including elemental oxygen. Oxidation under alkaline conditions normally gives the tetrapositive (Sn4+) state.

8 0
3 years ago
What is the de Broglie wavelength, in cm, of a 11.0-g hummingbird flying at 1.20 x 10^2 mph?
KonstantinChe [14]

Answer:1.123 x 10^-31cm

Explanation:

mass of humming bird=  11.0g

speed= 1.20x10^2mph

but I mile = 1.6m

1km=1000

I mile = 1.6x10^3m

1.20x10^2mph= 1.6x10^3m /1mile x at 1.20 x 10^2

=1.932 x10^5m

recall that  

1 hr= 60 min

1 min=60 secs, 1hr=3600s

Speed = distance/ time

=1.932 x10^5 / 3600= 5.366 x 10 ^1 m/s

m= a 11.0g= 11.0 x 10^-3kg

h=6.626*10^-34 (kg*m^2)/s

Wavelength = h/mu

= 6.626*10^-34/(11 x 10^-3 x 5.366x 10^1)

6.63x10^-34/ 590.26x 10 ^-3= 1.123 x10^-33m

but 1m = 100cm

1.123 x 10 ^-33 x 100 = 1.123 x 10^-31cm

de broglie wavelength of humming bird = 1.123 x 10 ^-31cm

5 0
3 years ago
Carson’s class visited a hydroelectric plant on a field trip during their study of energy. The process interested him, and he ha
AURORKA [14]

Answer:

look in your science book

Explanation:

7 0
2 years ago
The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga
Rashid [163]

Answer:

Final temperature of the gas is  576 ^{0}\textrm{C}.

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

                                       \frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

where V_{1} and V_{2} are volume of gas at T_{1} and T_{2} temperature (in kelvin scale) respectively.

Here V_{1}=158mL , T_{1}=(273+25)K=298K and V_{2}=450mL

So  T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K 

849 K = (849-273) ^{0}\textrm{C} = 576 ^{0}\textrm{C}

So final temperature of the gas is  576 ^{0}\textrm{C}.

3 0
3 years ago
In eukaryotes, the process of cell division is called mitosis true or false quick pls :)
mamaluj [8]
True. Mitosis is a part of the call cycle when replicated chromosomes are separated into new nuclei. It is a for if eukaryotic cell division that produces two daughter cells with the same genetic components as the parent cells.
6 0
3 years ago
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