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3 years ago

Calculate the molarity of hydroxide ion in an aqueous solution that has a poh of 5.00

Chemistry

1 answer:

Simora [160]3 years ago

4 0

Answer:

1.00 x 10^-5 M

Explanation:

pOH=-log[OH^-]

[OH^-]=10^(-pOH)

=10^-5

=1.00 x 10^-5 M

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Explanation:

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3 years ago

How to find the Ka of an acid?

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3 years ago

1. Because its structure is more complex,

Mashutka [201]

Answer:

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3 years ago

If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.

AVprozaik [17]

Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
------------------------------------------------------------------------------------------------------
Find pH

pH = -log(1 * 10^-1)
pH = 1
------------------------------------------------------------------------------------------------------
Find pOH
1 + pOH = 14

pOH = 13
------------------------------------------------------------------------------------------------------
Find OH-
[OH-] = 10^(-pOH)
[OH-] = 1 * 10^-13mo/L

The answer is $[OH-] = 1 * 10^{-13} mol/L$

Hope this helps!

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3 years ago