Answer:47.05% is the percent yield of nitrogen in the reaction.
Explanation:
heoretical yield of nitrogen gas = x
Moles of ammonia =
According to reaction,2 moles of ammonia gives 1 mol of nitrogen gas.
Then 2.3529 mol of ammonia will give:
of nitrogen gas
Mass of 1.1764 moles of nitrogen gas,x = 1.1764 mol × 28 g/mol=32.94 g
Experiential yield of nitrogen gas = 15.5 g
Percentage yield:
hope that help
47.05% is the percent yield of nitrogen in the reaction.
The answer is: the rate of reaction is 850 g/min.
n(P₄O₁₀) = 1.5 mol; amount of product.
M(P₄O₁₀) = 283.9 g/mol; molar mass of phosphorus(V) oxide.
m(P₄O₁₀) = n(P₄O₁₀) · M(P₄O₁₀).
m(P₄O₁₀) = 1.5 mol · 283.9 g/mol.
m(P₄O₁₀) = 425.85 g in 30 seconds.
Make proportion: 425 g : 30 s = m(P₄O₁₀) : 60 s.
m(P₄O₁₀) = 850 g in 60 s.
Answer:
[NH₃] → 3.24 M
Explanation:
Our solute: Ammonia
Our solvent: Water
Solution's mass = Mass of solute + Mass of solvent
Solution's mass = 15 g + 250 g = 265g
We use density to determine, the volume.
D = mass /volume → Volume = m / D → 265 g /0.974 g/mL = 272.07 mL.
We convert the mL to L → 272.07 mL . 1L /1000mL = 0.27207 L
To determine molarity we need the moles of solute in 1 L of solution.
Moles of solute are: 15g / 17g/mol = 0.882 moles
[NH₃] = 0.882mol /0.27207 L → 3.24 M
Answer:
The following formula is used to calculate the speed or velocity of a wave. V = f * w Where V is the velocity (m/s) f is the frequency (hz)
Answer:
b,d,f
Explanation:your welcome give brainilest
