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34kurt
3 years ago
9

PLS HELP 9,10,11!!! ASAP

Mathematics
1 answer:
taurus [48]3 years ago
7 0

Answer:

idk hff 8gciy ctcs 6rxtc igv6rx8

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HELP ASAP NEED HELPPP
Sloan [31]
Make everything equal to 360 degrees
x + 73 + 62 + 66 + x + 57 = 360
2x + 258 = 360
2x = 102
x = 51
6 0
4 years ago
use the change of base formula to evaluate log[3](58). then convert log[3](58) to a logarithm in base 4?
devlian [24]
Log[3](58)=3.69597450
log[3](58) to a logarithm in base 4= 167.957<span>
if you still need it.</span>
3 0
3 years ago
9. Solve the following system of equations. x + 2y − 6 = z 3y − 2z = 7 4 + 3x = 2y − 5z A. x = 0, y = 5, z = 4 B. C. D. x = 2, y
Inessa [10]
X + 2y - 6 = z..........x + 2y - z = 6
3y - 2z = 7
4 + 3x = 2y - 5z.....3x - 2y + 5z = -4

x + 2y - z = 6.....multiply by -3
3x - 2y + 5z = -4
---------------------
-3x - 6y + 3z = -18 (result of multiplying by -3)
3x - 2y + 5z = -4
--------------------add
-8y + 8z = - 22

-8y + 8z = -22
3y - 2z = 7 .....multiply by 4
----------------
-8y + 8z = -22
12y - 8z = 28 (result of multiplying by 4)
----------------add
4y = 6
y = 6/4 reduces to 3/2

-8y + 8z = -22
-8(3/2) + 8z = -22
-12 + 8z = -22
8z = -22 + 12
8z = -10
z = -10/8 reduces to -5/4

x + 2y - 6 = z
x + 2(3/2) - 6 = -5/4
x + 3 - 6 = -5/4
x - 3 = -5/4
x = -5/4 + 3
x = -5/4 + 12/4
x = 7/4

solution is (7/4, 3/2, -5/4).....x = 7/4, y = 3/2, and z = -5/4
4 0
4 years ago
Some people think it is unlucky if the 13th day of a month falls on a Friday. Show that in every calendar year (non leap or leap
MakcuM [25]
We will set a variable, d,  to represent the day of the week that January starts on.  For instance, if it started on Monday, d + 1 would be Tuesday, d + 2 would be Wednesday, etc. up to d + 6 to represent the last day of the week (in our example, Sunday).  The next week would start over at d, and the month would continue. For non-leap years:
If January starts on <u>d</u>, February will start 31 days later.  Following our pattern above, this will put it at <u>d</u><u> + 3</u> (28 days would be back at d; 29 would be d+1, 30 would be d+2, and 31 is at d+3).  In a non-leap year, February has 28 days, so March will start at <u>d</u><u>+3</u> also.  April will start 31 days after that, so that puts us at d+3+3=<u>d</u><u>+6</u>.  May starts 30 days after that, so d+6+2=d+8.  However, since we only have 7 days in the week, this is actually back to <u>d</u><u>+1</u>.  June starts 31 days after that, so d+1+3=<u>d</u><u>+4</u>.  July starts 30 days after that, so d+4+2=<u>d</u><u>+6</u>.  August starts 31 days after that, so d+6+3=d+9, but again, we only have 7 days in our week, so this is <u>d</u><u>+2</u>.  September starts 31 days after that, so d+2+3=<u>d</u><u>+5</u>.  October starts 30 days after that, so d+5+2=d+7, which is just <u>d</u><u />.  November starts 31 days after that, so <u>d</u><u>+3</u>.  December starts 30 days after that, so <u>d</u><u>+5</u>.  Remember that each one of these expressions represents a day of the week.  Going back through the list (in numerical order, and listing duplicates), we have <u>d</u><u>,</u> <u>d,</u><u /> <u>d</u><u>+1</u>, <u>d</u><u>+2</u>, <u>d+3</u><u>,</u> <u>d</u><u>+3</u>, <u>d</u><u>+3</u>, <u>d</u><u>+4</u>, <u>d</u><u>+5</u>, <u>d</u><u>+5</u>, <u /><u /><u>d</u><u>+6</u><u /><u /> and <u>d</u><u>+6</u>.  This means we have every day of the week covered, therefore there is a Friday the 13th at least once a year (if every day of the week can begin a month, then every day of the week can happy for any number in the month).  
For leap years, every month after February would change, so we have (in the order of the months) <u></u><u>d</u>, <u>d</u><u>+3</u>, <u>d</u><u>+4</u>, <u>d</u><u />, <u>d</u><u>+2</u>, <u>d</u><u /><u>+5</u>, <u>d</u><u />, <u>d</u><u>+3</u>, <u>d</u><u /><u>+6</u>, <u>d</u><u>+1</u>, <u>d</u><u>+4</u>, a<u />nd <u>d</u><u>+</u><u /><u /><u>6</u>.  We still have every day of the week represented, so there is a Friday the 13th at least once.  Additionally, none of the days of the week appear more than 3 times, so there is never a year with more than 3 Friday the 13ths.<u />
5 0
3 years ago
sketch and label all possible rectangles with a perimeter of 30 cm and sides whose lengths are whole numbers
Ivahew [28]
Its asking you to draw rectangles with sides that equal 30 cm for example 

3 0
4 years ago
Read 2 more answers
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