Answer:
KL = 27
JK = 16
MK = 30
NL = 23
m∠JKL = 132°
m∠KLJ = 22°
m∠KMJ = 54°
m∠KJL = 26°
Step-by-step explanation:
The given parameters of the quadrilateral JKLM are;
JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22
Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram
Therefore;
KL = JM = 27
JK = ML = 16
m∠KLJ = m∠MJL = 22°
MN = NK = 15
MK = MN + NK = 15 + 15 = 30
NL = JL/2 = 46/2 = 23
m∠KJM = m∠KLM = 48°
m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°
m∠KML = m∠JKM = 78°
m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°
m∠MKL = 54°
m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°
m∠KMJ = m∠MKL = 54°
Option D:
is the domain of the function.
Solution:
Given function is

<u>To find the domain of the function:</u>
Option A: 
Substitute x = 0 in r(x).

If x = 0, then r(0) = 0
So that x ≠ 0 is false.
So,
is not the domain of the function.
Option B: 
Substitute x = –1 in r(x).

If x = –1, then r(–1) = 1
So that x = ± 1 is false.
So,
is not the domain of the function.
Option C: 
Substitute x = 1 in r(x).

It is indeterminate.
So, all real numbers are not the domain of the function.
Option D: 
Substitute x = 1 in r(x).

It is indeterminate.
So,
is the domain of the function.
Answer:
answer varies on duration of trip
Step-by-step explanation:
it depends how long your trip is
To find the area of a rhombus, multiply the two diagonals together then divide by 2.
Area = 20 *15 = 300 / 2 = 150 sq. units.
Answer:
D. They have the same slope ( rate of change) and the same y-intercept.
Step-by-step explanation:
I y = 1.2x + 0.4.
II The slope is (10-4)/(8-3) = 6/5= 1.2.
Its equation is
y - 4 = (1.2)(x - 3)
y = 1.2x - 3.6 + 4
y = 1.2x + 0.4.