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kolezko [41]
4 years ago
15

25 problems.you have done 20% how many problems have you done

Mathematics
2 answers:
Kitty [74]4 years ago
8 0
25 problems and you have done 20%

= 20/100 * 25
= 0.2 * 25
= 5
You have done 5 problems out of 25
Lemur [1.5K]4 years ago
3 0
20% is 1/5 of the 25 problems, so 1/5 of 25 is equal to 5 (25/5=5)
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X/3 - ( -2) =16 and its 7 th grade algebra btw i need help
Novosadov [1.4K]

Answer x/3 -(-2)= 16

X/3+ 2=16

X/3=16-2

X/3=14

X= 14x3=42

Step-by-step explanation:

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3 years ago
Pls answer this (aka Sophia lol)
s2008m [1.1K]

Answer:

1. 44 GB

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Is 6-6 and 1-6 equal
uranmaximum [27]

Answer:

no

Step-by-step explanation:

6-6=0

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3 years ago
Suppose the standard deviation of X is 6 and the standard deviation of Y is 8. Answer the following two questions, rounding to t
Darina [25.2K]

Recall that

Var[<em>aX</em> + <em>bY</em>] = <em>a</em> ² Var[<em>X</em>] + 2<em>ab</em> Cov[<em>X</em>, <em>Y</em>] + <em>b</em> ² Var[<em>Y</em>]

Then

Var[3<em>X</em> - 7<em>Y</em>] = 9 Var[<em>X</em>] - 42 Cov[<em>X</em>, <em>Y</em>] + 49 Var[<em>Y</em>]

Now, standard deviation = square root of variance, so

Var[3<em>X</em> - 7<em>Y</em>] = 9×6² - 42×2 + 49×8² =  3376

The general result is easy to prove: by definition,

Var[<em>X</em>] = E[(<em>X</em> - E[<em>X</em>])²] = E[<em>X </em>²] - E[<em>X</em>]²

Cov[<em>X</em>, <em>Y</em>] = E[(<em>X</em> - E[<em>X</em>]) (<em>Y</em> - E[<em>Y</em>])] = E[<em>XY</em>] - E[<em>X</em>] E[<em>Y</em>]

Then

Var[<em>aX</em> + <em>bY</em>] = E[((<em>aX</em> + <em>bY</em>) - E[<em>aX</em> + <em>bY</em>])²]

… = E[(<em>aX</em> + <em>bY</em>)²] - E[<em>aX</em> + <em>bY</em>]²

… = E[<em>a</em> ² <em>X</em> ² + 2<em>abXY</em> + <em>b</em> ² <em>Y</em> ²] - (<em>a</em> E[<em>X</em>] + <em>b</em> E[<em>Y</em>])²

… = E[<em>a</em> ² <em>X</em> ² + 2<em>abXY</em> + <em>b</em> ² <em>Y</em> ²] - (<em>a</em> ² E[<em>X</em>]² + 2 <em>ab</em> E[<em>X</em>] E[<em>Y</em>] + <em>b</em> ² E[<em>Y</em>]²)

… = <em>a</em> ² E[<em>X</em> ²] + 2<em>ab</em> E[<em>XY</em>] + <em>b</em> ² E[<em>Y</em> ²] - <em>a</em> ² E[<em>X</em>]² - 2 <em>ab</em> E[<em>X</em>] E[<em>Y</em>] - <em>b</em> ² E[<em>Y</em>]²

… = <em>a</em> ² (E[<em>X</em> ²] - E[<em>X</em>]²) + 2<em>ab</em> (E[<em>XY</em>] - E[<em>X</em>] E[<em>Y</em>]) + <em>b</em> ² (E[<em>Y</em> ²] - E[<em>Y</em>]²)

… = <em>a</em> ² Var[<em>X</em>] + 2<em>ab</em> Cov[<em>X</em>, <em>Y</em>] + <em>b</em> ² Var[<em>Y</em>]

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3 years ago
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WITCHER [35]

Answer:

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Step-by-step explanation:

S - 1.7x = 5.2

x = 2006 - 1998 = 8

S - 1.7(8) = 5.2

S - 13.6 = 5.2

S = 5.2 + 13.6

S = 18.8

3 0
4 years ago
Read 2 more answers
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