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den301095 [7]
2 years ago
11

The length of a cell phone is 1.61.6 inches and the width is 4.64.6 inches. The company making the cell phone wants to make a ne

w version whose length will be 2.162.16 inches. Assuming the side lengths in the new phone are proportional to the old phone, what will be the width of the new phone?
Mathematics
1 answer:
Mashcka [7]2 years ago
4 0

Answer: 4.25 inches

DO NOT DEPEND ON MY ANSWER

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Please help me with this and explain how u did it step by step
joja [24]

The domain of the third piece of the graph is contained in interval <u>B. (12, 20)</u>.

<h3>What is the domain of a graph?</h3>

The domain of a graph consists of all the input values shown on the x-axis.

The input values (domain) are shown on the x-axis, unlike the range, whose output values are shown on the y-axis.

Therefore, the domain comprises the independent variables or values, which can be determined using the function, y = f(x).

Thus, the domain of the third piece of the graph can be determined in interval <u>B. (12, 20)</u>.

Learn more about domain and range at brainly.com/question/10197594 and brainly.com/question/2264373

#SPJ1

6 0
2 years ago
Find the surface area of a rectangular prism with length 18 inches, width 6 inches, and height 4 inches.
Sever21 [200]
If its volume (Not so sure about surface area?) than its 432 inches^3
4 0
3 years ago
Point (k, -3) lies on the line whose equation is x-2y=-2. What is the value of k?
natita [175]

Answer:

Substitute, <em><u>y = -3</u></em> and <em><u>x = k</u></em> on the equation.

=> k - 2×(-3) = -2

=> k = -2 + (-6)

=> k = - 8

=================

<h2>HOPE U UNDERSTOOD</h2><h3>MARK AS BRAINLIEST ONE</h3>

Any Doubts? Please COMMENT

7 0
3 years ago
GJ is a midsegment of triangle DEF, and HK is a midsegment of triangle GFJ. What is the length of HK?
loris [4]

Answer:

Option B) 4 centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of n

we know that

a) GJ is a midsegment of triangle DEF

then

G is the midpoint segment DF and J is the midpoint segment EF

DG=GF and EJ=JF

b) HK is a midsegment of triangle GFJ

then

H is the midpoint segment GF and K is the midpoint segment JF

GH=HF and JK=KF

In this problem we have

HF=7 cm

so

GH=7 cm

GF=GH+HF ----> by addition segment postulate

GF=7+7=14 cm

Remember that

DG=GF

substitute the given values

2n-1=14

solve for n

2n=14+1

2n=15

n=7.5\ cm

step 2

Find the length of GJ

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

so

GJ=\frac{1}{2}DE

we have

GE=2n+1=2(7.5)+1=16\ cm

substitute

GJ=\frac{1}{2}16=8\ cm

step 3

Find the length of HK

we have that

HK=\frac{1}{2}GJ ----> by the midpoint theorem

we have

GJ=8\ cm

substitute

HK=\frac{1}{2}8=4\ cm

7 0
3 years ago
Pls hurry i really i need to finish
Thepotemich [5.8K]
0,0
1,2
2,4
3,6
4,8
There u go hope u get it done
5 0
1 year ago
Read 2 more answers
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