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vitfil [10]
3 years ago
5

$800 principal earning 7%, compounded annually, after 4 years

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

$1050

Step-by-step explanation:

<h2><u>formula for compound interest method:</u></h2>

A = P ( 1 + r/100)^n

A is actual amount

r is the rate of interest

P is the principle

n is the number of years

A = 800 (1 * 7/100)^4

= 1048.637

to 3sf = <u>$1050</u>

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The cost of printing a catalog of the products that your company distributes is a flat rate of $52 plus $0.20 per copy. Let C re
yanalaym [24]
Given:
Cost of printing a catalog: flat rate of $52 and $0.20 per copy.

C = 52 + 0.20x

C is the total cost of printing x number of copies.

x = 500
C = 52 + 0.20(500) = 52 + 100 = 152

x = 1000
C = 52 + 0.20(1000) = 52 + 200 = 252

x = 1500
C = 52 + 0.20(1500) = 52 + 300 = 352

x = 2000
C = 52 + 0.20(2000) = 52 + 400 = 452

x = 2500
C = 52 + 0.20(2500) = 52 + 500 = 552


4 0
3 years ago
Read 2 more answers
The HCF of 60 and 108 is 12. write their LCM
damaskus [11]

Answer:

What is the LCM of 60 and 108? The LCM of 60 and 108 is 540.

Step-by-step explanation:

What is the LCM of 60 and 108? The LCM of 60 and 108 is 540.

7 0
2 years ago
If 3 to the power y = x then y = ?
Oksanka [162]

Answer:

y=\log_3(x)


Step-by-step explanation:

3^y=x

\ln(3^y)=\ln(x)

y\ln(3)=\ln(x)

y=\frac{\displaystyle\ln(x)}{\displaystyle\ln(3)}

but if

f(x)=\frac{\displaystyle\ln(x)}{\displaystyle\ln(3)}

then since

f(3)=\frac{\displaystyle\ln(3)}{\displaystyle\ln(3)}=1

f(x)=\log_3(x)

so

y=\log_3(x)


or


3^y=x

\log_3(3^y)=\log_3(x)

y\log_3(3)=\log_3(x)

\text{but }\,\log_3(3)=1, \text{so,}

y=\log_3(x)



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3 years ago
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Elden [556K]

Given:

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The correct option that represents the given construction.

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The steps for the given figure are:

1. Draw a ray PQ.

2. Mark an arc BC on the given angle and mark the same arc on the line and the intersection of line and arc is point Q.

3. Set the compass of the length BA.

4. Put the compass on the point Q mark arc that intersect the first arc. The intersection of arcs is R.

5. Draw a ray PR.

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Answer:


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