Answer:
Hydrometers
Density can be measured using a variety of instruments. A hydrometer is used to determine the density
Explanation:
Explanation:
The given balanced reaction is as follows.

It is given that mass of ammonium nitrate is 86.0 kg.
As 1 kg = 1000 g. So, 86.0 kg = 86000 g.
Hence, moles of
present will be as follows.
Moles of
= 
= 
= 1074.42 mol
Therefore, moles of
,
and
produced by 1074.42 mole of
will be as follows.
Moles of
= 
= 537.21 mol
Moles of
= 
= 1074.42 mol
Moles of
= 
= 2148.84 mol
Therefore, total number of moles will be as follows.
537.21 mol + 1074.42 mol + 2148.84 mol
= 3760.47 mol
According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.
PV = nRT
1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex] (as
= 307 + 273 = 580 K)
V = 179066.06 L
Thus, we can conclude that total volume of the gas is 179066.06 L.
There are several differences between<span> a </span>physical and chemical change<span> in matter or substances. A </span>physical change<span> in a substance doesn't </span>change<span> what the substance is. In a </span>chemical change<span> where there is a </span>chemical<span> reaction, a new substance is formed and energy is either given off or absorbed.</span>
The alcohol concentration of the mixed solution is 20%
Simplification :
Based on the given condition, formulate :
35% ×0.40 + 0.6 ×10% ÷{ 0.4+0.6}
Calculate the product :
Calculate the sum or difference : 
Any fraction with denominator 1 is equal to numerator : 0.2
Multiply a number to both numerator, denominator : 0.2 ×
Calculate the product or quotient : 
A fraction with denominator equals to 100 to a percentage 20%.
How do you find the concentration of a mixed solution?
In general when your are mixing two different concentrations together first calculate number of moles for each solution (n=CV ,V-in liter) then add them together it will be total moles,then concentration of mixture will be = total moles / total volume(liter).
Learn more about concentration of alcohol :
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The chemical formula for aluminum flouride is C). AlF3.