To solve this problem, we should recall that
the change in enthalpy is calculated by subtracting the total enthalpy of the reactants
from the total enthalpy of the products:
ΔH = Total H of products – Total H of reactants
You did not insert the table in this problem, therefore I
will find other sources to find for the enthalpies of each compound.
ΔHf CO2 (g) = -393.5 kJ/mol
ΔHf CO (g) = -110.5 kJ/mol
ΔHf Fe2O3 (s) = -822.1 kJ/mol
ΔHf Fe(s) = 0.0 kJ/mol
Since the given enthalpies are still in kJ/mol, we have to
multiply that with the number of moles in the formula. Therefore solving for ΔH:
ΔH = [<span>3 mol </span><span>( − </span><span>393.5 </span>kJ/mol<span>) + 1 mol (</span>0.0
kJ/mol)<span>] − [</span><span>3 mol </span><span>( − </span><span>110.5 </span>kJ/mol<span>) + </span><span>2 mol </span><span>( − </span><span>822.1 </span>kJ/mol<span>)]</span>
ΔH = <span>795.2
kJ</span>
Answer:
A. Protein disulfide is oxidized.
Explanation:
When thiol reagents are introduced with some protein solutions they react with molecules of disulfide and oxidize the protein. There occurs inter-conversion of thiol molecules into free disulfide molecules. The DTT reduces the disulfide molecules bonds of proteins and it starts to peptide.
They all have 2 elections in the outer S orbital, and 4 electrons in the P orbitals.
Answer:
3,3-Dimethyloct-4-yne · Contents · 1Structures · 2Names and Identifiers · 3Chemical and Physical Properties · 4Related Records · 5 Patents · 6 ..
I believe that the answer is A. Decaying
