Answer:
141g of CCl₄
Explanation:
First, we have to write the balanced equation.
CCl₄(g) + 2 HF(g) ⇄ CF₂Cl₂(g) + 2 HCl(g)
We can calculate how many moles of CF₂Cl₂ using the ideal gas equation.
V = 14.9 dm³ = 14.9 L
T = 21°C + 273.15 = 294.15 K
P = 1.48 atm
R = 0.08206 atm.L/mol.K

We can use proportions to find the mass of CCl₄ required to obtain 0.914 moles of CF₂Cl₂. According to the balanced equation, 1 mol of CF₂Cl₂ is produced when 1 mol of CCl₄ reacts. And the molar mass of CCl₄ is 154 g/mol.

Well to find speed you have to do distance /time. So, in this case you do 112m /29s which it will be 3.862 which if you round it, it will be 3.86 m/s
Answer: M = 22/ (i x28.948)
Explanation:
Pi = osmotic pressure = 22atm
T = Temperature = 353K
M = Molarity = ?
R = gas constant = 0.082atm.L/mol/K
i = van’t Hoff factor
Pi = iMRT
M= Pi /(iRT) = 22 / ( i x 0.082 x 353)
M = 22/ (i x28.948)
Answer:
of PABA is 0.000022
Explanation:

cM 0 0

So dissociation constant will be:

Give c= 0.055 M and
= ?

![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![2.96=-log[H^+]](https://tex.z-dn.net/?f=2.96%3D-log%5BH%5E%2B%5D)
![[H^+]=1.09\times 10^{-3}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1.09%5Ctimes%2010%5E%7B-3%7D)
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)


Putting in the values we get:


Thus
of PABA is 0.000022