Azeotropic mixture. I think
The actual yield is 43 g Cl₂.
The <em>limiting reactant was MnO₂</em> because it gave the smaller mass of Cl₂.
∴ The <em>theoretical yield</em> is 60.25 g Cl₂.
% yield = actual yield/theoretical yield × 100 %
Actual yield = theoretical yield × (% yield/100 %) = 60.25 g × (72 %/100%) = 43 g
B is the answer to your question
Answer:
6 carbon atoms
Explanation:
For instance, we can say that one molecule of glucose has 6 carbon atoms, or we can say, equivalently, that one mole of glucose has 6 moles of carbon atoms
Vertical now I need to fill 20 characters
