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Nady [450]
2 years ago
13

What is the ratio of the areas of the signals in the h nmr spectrum of pentan-3-ol?

Chemistry
1 answer:
Damm [24]2 years ago
8 0

The ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

<h3>What is a NMR spectrum?</h3>

Nuclear magnetic resonance spectroscopy is a spectroscopy that shows the detailed structure and chemical environment of a chemical element.

Pentan-3-ol contain 12 hydrogen atoms. In H-NMR spectra, hydrogen atoms have same environment gives a signal.

There are 4 different kinds of signals due of the 4 different environment experienced by these 12 hydrogens.

Thus, the  ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

Learn more about NMR spectrum

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Why melting and boiling points can be used as a way to check purity?​
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Answer: Let's see why

Pure solid and liquid compounds possess sharp melting and boiling points. Therefore, melting and boiling points of a compound can be used as a criteria of purity. ... Sometimes during cooling minute quantity of the substance (solid which is being purified) is added to the solution to facilitate the initial crystallisation.

Explanation:

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2 years ago
Atoms of _______ gain electrons to fill their outer electron shells and become ________ ions.
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Nonmetals and negative. Answer is c
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During action potential, positively charged ________ ions move inside the cell.
Tems11 [23]

During action potential, positively charged  sodium ions move inside the cell.

So option D is correct one.

The sodium ion moves inside the cell during a action potential. The stage of action potential is called depolarization . This open voltage gated sodium channel.

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It consists of phases:

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An active potential propagates along the cell membrane of an axon until  it reaches the terminal button.

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8 0
2 years ago
A sample of hydrated copper (II) sulfate (CuSO4•nH2O) is heated to 150°C and produces 103.74 g anhydrous copper (II) sulfate and
wariber [46]

Answer:

5

Explanation:

Firstly, we convert what we have to percentage compositions.

There are two parts in the molecule, the sulphate part and the water part.

The percentage compositions is as follows:

Sulphate- (103.74)/(103.74 + 58.55) × 100% = apprx 64%

The water part = 100 - 64 = 36%

Now, we divide the percentages by the molar masses.

For the CuSO4 molar mass is 64 + 32 + 4(16) = 160g/mol

For the H2O = 2(1) + 16 = 18g/mol

Now we divide the percentages by these masses

Sulphate = 64/160 = 0.4

Water = 36/18 = 2

The ratio is thus 0.4:2 = 1:5

Hence, there are 5 water molecules.

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3 years ago
Sean drew this diagram and labeled an unknown gas as gas A. Which gas does A represent?
ANEK [815]
Gas A is Carbon Dioxide
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3 years ago
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