Answer: Concentration of N₂ is 4.8.
M.
Explanation: 
is a constant of equilibrium and it is dependent of the concentrations of the reactants and the products of a balanced reaction. For
N2(g) + 2 O2(g) ⇄ 2 NO2(g)
= ![\frac{[NO2]^{2} }{[N2][O2]^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNO2%5D%5E%7B2%7D%20%7D%7B%5BN2%5D%5BO2%5D%5E%7B2%7D%20%7D)
From the question concentration of NO2 is twice of O2:
[NO2] = 2[O2]
Substituting this into :
= ![\frac{[2O2]^{2} }{[N2][O2]^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2O2%5D%5E%7B2%7D%20%7D%7B%5BN2%5D%5BO2%5D%5E%7B2%7D%20%7D)
8.3.
= ![\frac{4O2^{2} }{[N2].O2^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B4O2%5E%7B2%7D%20%7D%7B%5BN2%5D.O2%5E%7B2%7D%20%7D)
[N2] = 
[N2] = 
[N2] = 4.8.
The concentration of N2 in the equilibrium is [N2] = 4.8.M.
Answer 2.04
Explanation
Electronegativity decreases down the group and increases across the period in the periodic table.
In the period two of the periodic table,we have the following values for electronegativities with respect to its elements.
Li...........0.98
Be.........1.57
B..........2.04
C.........2.55
N..........3.04
O...........3.44
F...........3.98
Ne........n.a
The value that should be where M is is 2.04
Answer:
The pressure is 1, 22 atm.
Explanation:
We use deal gas formula. First, we convert the unit of temperature in Celsius into Kelvin. We use the constant R= 0,082 l atm /K mol.Then, we solve P (pressure).
0°C=273 K 25°C= 273 + 25= 298 K
PV=nRT -----> P= (nRT)/V
P= (0,5 mol x 0,082 l atm /K mol x 298 K)/ 10 L
<em>P= 1, 2218 atm</em>
100 m = 0.1 km
9.58 sec = 9.58/3600 = 0.00266 hr
Speed = 0.1/0.00266= 37.6 km/hr
Can you mark it brainliest?
