All categories

4 years ago

How can the decimal -70.73 be written as a mixed number

Mathematics

2 answers:

zepelin [54]4 years ago

8 0

Like so:
-70 $\frac{73}{100}$

vitfil [10]4 years ago

3 0

Answer:

$-70\frac{73}{100}$

Step-by-step explanation:

Given : -70.73

To Find: how can the decimal -70.73 be written as a mixed number

Solution:

Number = -70.73

Fraction= $-\frac{7073}{100}$

Quotient = 70

Remainder = 73

Divisor =100

Mixed fraction : $-70\frac{73}{100}$

Hence the decimal -70.73 be written as $-70\frac{73}{100}$

You might be interested in

Help me with this pls

Akimi4 [234]

Answer:

is that math????????????????

3 0

3 years ago

Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

4 years ago

What is slope-intercept form?

krok68 [10]

Solpe intercpt form is y=mx+b
m=slope
b=y intercept
so exg
if you have
3x+8y=8
subtract 3x from both sides
8y=3x+8
divide boh tsides by 8
y=8/3x+1
y intercpt=1
slope=8/3

7 0

3 years ago

Read 2 more answers

Can someone explain how to solve and graph this step-by-step?

Maslowich

(x,y)=(2,1) where the two lines intercept
so for the first equation you go on the y line and dot -4 then count up 5 times then right 2 times since it’s rise over run
for the second line start at positive 3 on the y line then it’s -1/1 which is up once and left once cause of the negative

7 0

3 years ago

What is the volume of the cube?

Jobisdone [24]

27 cubic inches
Because you multiply 3x3x3=27

4 0

3 years ago